Charles, a security analyst, needs to check his network for vulnerabilities. he wants a scan that interacts with network nodes and repairs security issues found. The kind of scanning that best describes Charles's requirements is: Active scanning.
<h3>Who is a Security Analyst?</h3>
A Security Analyst's responsibilities include the following:
Define, plan, execute, maintain, and improve security measures, policies, and controls. Writing reports and offering insights on the effectiveness of current security policies, incident response plans, disaster recovery plans, and other security-related information
Active scanning is a scanning approach that involves scanning individual endpoints in an IT network in order to retrieve more specific information.
Learn more about Security Analysts:
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Disk defragmentation realigns separated data so that related file pieces are unified. <span> Defragmentation is is the process of consolidating fragmented files on the user's hard drive.</span>This Microsoft Windows utility includes <span>rearranging the fragments and restoring them into fewer fragments or into the whole file.
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Answer:
Written in C++
void number(int n){
if(n%2 == 0)
cout<<2 * n;
else
cout<<5 * n;
}
Explanation:
The programming language is not stated.
However, I answered using C++
This line defines the function as void
void number(int n){
This line checks if the number is even
if(n%2 == 0)
If yes, it doubles the number and prints the output
cout<<2 * n;
If otherwise,
else
It multiplies the number by 5 and prints the output
cout<<5 * n;
}
To call the function from main, use:
number(n);
Note than n must be declared as integer
See attachment
