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Alex Ar [27]
3 years ago
11

Write an application named [LastName]_MultiplicationTable and create a method that prompts the user for an integer value, for ex

ample 7. Then display the product of every integer from 1 through 10 when multiplied by the entered value. For example, the first three lines of the table might read 1 x 7 = 7, 2 x 7 = 14, 3 x 7 = 21. .. . ..
Computers and Technology
1 answer:
WITCHER [35]3 years ago
7 0

Answer:

I did this in C# & Java

Explanation:

C#:

       public static void Main(string[] args)

       {

           int input = Convert.ToInt32(Console.ReadLine());

           Multiply(input);

       }

       public static int Multiply(int input)

       {

           int ans = 0;

           for(int i =1; i<=10; i++)

           {

               ans = i*input;

               Console.WriteLine(i + "*" + input + "=" + ans);

           }

           return ans;

       }

Java:

   public static void main(String[] args)

   {

       Scanner myObj = new Scanner(System.in);  

       int input = Integer.parseInt(myObj.nextLine());

       Multiply(input);

   }

   public static int Multiply(int input)

   {

       int ans = 0;

       for(int i =1; i<=10; i++)

           {

               ans = i*input;

               System.out.println(i + "*" + input + "=" + ans);

           }

       return ans;

   }

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Write a program that declares an array named myArray with 8 components of the type int. Initialize the array to 8 values that th
Savatey [412]

Answer:

#include <iostream>

using namespace std;

void filterEvens(int myArray[]) {

   for (int i = 0; i < 8; ++i) {

     if(myArray[i]%2==0){

         cout<<myArray[i]<<" ";

     }

  }

}

int main(){

   int myArray[8];

   for(int i =0;i<8;i++){

       cin>>myArray[i];

   }

   filterEvens(myArray);

   return 0;

}

Explanation:

The solution is provided in C++

#include <iostream>

using namespace std;

The function filerEvens is defined here

void filterEvens(int myArray[]) {

This iterates through the elements of the array

   for (int i = 0; i < 8; ++i) {

This checks if current element is an even number

     if(myArray[i]%2==0){

If yes, this prints the array element

         cout<<myArray[i]<<" ";

     }

  }

}

The main begins here

int main(){

This declares an integer array of 8 elements

   int myArray[8];

The following iteration allows input into the array

<em>    for(int i =0;i<8;i++){</em>

<em>        cin>>myArray[i];</em>

<em>    }</em>

This calls the defined function filter Evens

   filterEvens(myArray);

   return 0;

}

6 0
3 years ago
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