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algol [13]
3 years ago
6

Which of the following activities are examples of data gathering?

Mathematics
2 answers:
Digiron [165]3 years ago
7 0
B and D
I think. let me know if it is correct.
Dafna11 [192]3 years ago
4 0

Answer:


Step-by-step explanation: asking 500 voters who they will vote for, measuring the temp of ice water

(apex)


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1. Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into
Ludmilka [50]

Answer:

5, assuming you get the worst possible slips off: 0,1,2,3,4

Step-by-step explanation:

5 0
3 years ago
A roofer sketches a diagram of a house on which he is working.
docker41 [41]
Using the SSA formula:

X = SQRT ( 40^2 + 26^2 - 2*40*26*cos(65))

X = SQRT(2276 - 2080*cos(65))

X = SQRT(1396.954)

X = 37.37 = 37.4 ft.
4 0
3 years ago
Read 2 more answers
BRAINLIEST ASAP! PLEASE HELP ME :)
Irina-Kira [14]

Answer:

○ \displaystyle 25\%

Step-by-step explanation:

3 → 13 − 16

\displaystyle \frac{Number\:of\:desired\:[favourable]\:outcomes}{Total\:number\:of\:possible\:outcomes} \\ \\ \frac{3}{12} = \frac{1}{4} = 25\%

I am joyous to assist you anytime.

4 0
3 years ago
Please help ill give you points
UkoKoshka [18]
Yes, it is a function
4 0
3 years ago
Read 2 more answers
One morning, John drive 5 hours before stopping to eat. After lunch, he. increased his speed by 10 mph. If he completed a 500-mi
Marrrta [24]
So  he drove 5hrs, before lunch, now, he was going at speed, say "r", after he ate, he sped up by 10mph, so, his rate is whatever "r" is, plus 10, or " r + 10 ", after lunch

we know the whole trip took 10hrs, so, is 5hrs before lunch and 5hrs after lunch

we also know the whole trip was 500miles, so if he drove, say "d" miles before lunch, after lunch he drove the slack after lunch, or " 200 - d "

recall, your d = rt, distance = rate * time

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{before lunch}&d&r&5\\
\textit{after lunch}&500-d&r+10&5
\end{array}
\\\\\\

\begin{cases}
\boxed{d}=5r\\
500-d=(r+10)5\\
----------\\
500-\boxed{5r}=(r+10)5
\end{cases}
\\\\\\
\cfrac{500-5r}{5}=r+10\implies 100-r=r+10

and I'm sure you know what that is
6 0
3 years ago
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