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3 years ago

How does the heating element of a portable electric heater work

2 answers:

4 0

The heating element of an electric heater works following the Joule's effect. In fact, the main component of the heating element is a resistor. When the heater is connected to the plug, electrical current starts flowing through the resistor. Because of the Joule's effect, the temperature of the resistor increases: therefore, the resistor gets hotter and releases heat to the surroundings.

Vaselesa [24]3 years ago

3 0

The element is a resistor, so some of the electrical energy flowing through the heating element is converted to thermal energy.

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Una pelota se desliza hacia arriba por una pendiente se halla inicialmente a 6m de la parte más baja de dicha pendiente y tiene

jolli1 [7]

Answer:

a) vprom = - 0.6 [m/s] b) ver explicacion c) vf = 10.8 [m/s]

Explanation:

Para poder solucionar este problema debemos completar el enunciado del problema así como la pregunta, realizando una búsqueda en Internet encontramos el enunciado completo, así como la pregunta.

"Una pelota que se desliza hacia arriba por una pendiente se halla inicialmente a 6 m de la parte más baja de dicha pendiente y tiene una velocidad de 4 m/s. Cinco segundos después se encuentra a 3 m de la parte más baja. Si suponemos una aceleración constante, "

¿cual fue la velocidad media?

¿Cuál es el significado de una velocidad media negativa?

¿Cuáles son la aceleración media y la velocidad final?

Para facilitar esta solución debemos realizar un esquema del movimiento de la pelota en el plano inclinado. En la imagen adjunta se puede ver un esquema del movimiento de la pelota sobre el plano inclinado en los diferentes tiempos mencionados.

¿cual fue la velocidad media?

La velocidad media se debe calcular utilizando la expresión de velocidad = espacio / tiempo.

$v_{prom}=x/t\\v_{prom}=(3-6)/5\\v_{prom}=-0.6 [m/s]$

¿Cuál es el significado de una velocidad media negativa?

La velocidad media negativa significa que se dirige hacia abajo en sentido contrario

¿Cuáles son la aceleración media y la velocidad final?

$x=v_{o}*t+0.5*a*t^{2} \\-3=(4)*(5)+0.5*a*(5)^2\\a=1.36[m/s^2]\\\\Velocity\\v_{f}=v_{o}+a*t = 4+(1.36*5)\\v_{f}=10.8[m/s]$

6 0

3 years ago

A moving walkway at an airport has a speed v1 and a length L. A woman stands on the walkway as it moves from one end to the othe

bearhunter [10]

Answer:

t=L/ $V_1$

Explanation:

solution:

Let E be an observer, and B a second observer traveling with velocity $V_{BE}$ as measured by E. If E measures the velocity of an object A as $V_{AE}$ then B will measure A velocity as

$V_{AB}$ = $V_{AE}$ - $V_{BE}$

Applied here,

the walkway (W) and the man (M) are moving relative to Earth (E}, the velocity of the man relative to the moving walkway is

$V_{MW}$ = $V_{ME}$ - $V_{WE}$

$V_1=V_{WE}$ ,

$V_2=V_{MW}$

The time required for the woman, traveling at constant speed $V_1$ relative to the ground, to travel distance L relative to the ground is :

t=L/ $V_1$

3 0

4 years ago

AP PHYSICS SYSTEM OF EQUATIONS

Anon25 [30]

Walking at a speed of 2.1 m/s, in the first 2 s John would have walked

(2.1 m/s) (2 s) = 4.2 m

Take this point in time to be the starting point. Then John's distance from the starting line at time t after the first 2 s is

J(t) = 4.2 m + (2.1 m/s) t

while Ryan's position is

R(t) = 100 m - (1.8 m/s) t

where Ryan's velocity is negative because he is moving in the opposite direction.

(b) Solve for the time when they meet. This happens when J(t) = R(t) :

4.2 m + (2.1 m/s) t = 100 m - (1.8 m/s) t

(2.1 m/s) t + (1.8 m/s) t = 100 m - 4.2 m

(3.9 m/s) t = 95.8 m

t = (95.8 m) / (3.9 m/s) ≈ 24.6 s

(a) Evaluate either J(t) or R(t) at the time from part (b).

J (24.6 s) = 4.2 m + (2.1 m/s) (24.6 s) ≈ 55.8 m

8 0

3 years ago

A hockey player strikes a puck that is initially at rest. The force exerted by the stick on the puck is 975 N, and the stick is

Anna007 [38]

Explanation:

Given that,

The force exerted by the stick on the puck is 975 N

The stick is in contact with the puck for 0.0049 s

Initial speed of the puck, u = 0 (at rest)

(a) We need to find the impulse imparted by the stick to the puck.

Impulse = Force × time

J = 4.7775 kg-m/s

(b) Mass of the puck, m = 1.76 kg

We need to find the speed of the puck just after it leaves the hockey stick.

Let the speed be v.

As impulse is equal to the change in momentum.

$J=m(v-u)\\\\4.7775=1.67(v-0)\\\\v=\dfrac{4.7775}{1.67}\\\\v=2.86\ m/s$

So, when the puck leaves the hockey stick its speed is 2.86 m/s.

8 0

3 years ago

A golfer imparts a speed of 29.0 m/s to a ball, and it travels the maximum possible distance before landing on the green. the te

Roman55 [17]

Explanation:

It is given that,

Initial speed of a golfer, u = 29 m/s

If it travels the maximum possible distance before landing. It means that it is projected at an angle of 45 degrees.

(a) We need to find the time spent by the ball in the air. It can be calculated by using second equation of motion.

$s=ut+\dfrac{1}{2}at^2$

Here,

a = -g

s = 0 (it is displacement and it is equal to 0 as the ball lands on the green).

So,

$0=29\sin(45)t-\dfrac{1}{2}\times 9.8t^2\ (\text{Initial vertical component of velocity is taken})\\\\-4.9t^2+29\times \dfrac{1}{\sqrt2}t=0\\\\-4.9t^2+20.5t=0\\\\t=0,4.184\ s$

So, it will take 4.184 seconds in the air.

(b) let x is the longest hole in one that the golfer can make if the ball does not roll when it hits the green. It can be given by :

$x=vt\cos\theta\\\\x=29\times 4.184\times \cos(45)\\\\x=85.79\ m$

Hence, this is the required solution.

8 0

4 years ago