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rodikova [14]
3 years ago
6

You are watching a wave with a frequency of 512 Hz go past. How many peaks of the wave go past you each minute?

Physics
2 answers:
bija089 [108]3 years ago
6 0

Answer:

61440

Explanation:

The period of a sine wave is the length of one cycle of the wave and is characterized by having two peaks a negative and a positive (See the image).

The frequency on the waves is given in hz equivalent to one cycle per second, so 512 hz are 512 cycles per second, given that one minute is equivalent to 60 seconds we have a total of 60*512 = 30720 cycles per second, because each cycle contains two peaks the total amount of peaks in one minute is 30720 *2 =61440

inna [77]3 years ago
4 0

Answer:

61440 peaks

Explanation:

A hertz represents one cycle for every second:

f= Hz=\frac{1}{s}

So if a wave have frequency of 2Hz for example, this means the wave does two cycles per second.

Normally the waves are represented by cosine or sine waves. These kind of waves have two peaks in each cycle, one positive and one negative. With this in mind, let's calculate how many peaks of the wave pass each minute.

A minute has 60 seconds, hence:

60*512=30720\hspace{3}cycles\hspace{3}per\hspace{3}minute

And we know already that every cycle has two peaks, so:

30720*2=61440\hspace{3}peaks\hspace{3}per\hspace{3}minute

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What type of chemical weathering is caused when rocks sit in a pool of salwater?
sergiy2304 [10]

Answer:

weathering occurs when rocks sit in a pool of saltw ater.

Explanation:

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5 0
3 years ago
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A straight trail with a uniform inclination of 15 degrees leads from a lodge at an elevation of 600 feet to a mountain lake at a
9966 [12]

Answer:

The length of the trail = 22796 ft

Explanation:

From the ΔABC

AC = length of the trail = x

AB = 6100 - 600 = 5500 ft

Angle of inclination \theta = 15°

\sin \theta = \frac{AB}{AC}

\sin 15 = \frac{5900}{x}

x = \frac{5900}{0.2588}

x = 22796 ft

Since x = AC = Length of the trail.

Therefore the length of the trail = 22796 ft

7 0
3 years ago
In an experiment, a shearwater (a seabird) was taken from its nest, flown a distance 5220 km away, and released. It found its wa
Korolek [52]

Answer:

4.6834625323 m/s

0 m/s

Explanation:

s = Displacement

t = Time

Velocity is given by

v=\dfrac{s}{t}\\\Rightarrow v=\dfrac{5220000}{12.9\times 24\times 60\times 60}\\\Rightarrow v=4.6834625323\ m/s

The bird's average velocity for the return flight is 4.6834625323 m/s

In the whole episode the bird went 5220 km away from its nest and came back. This means the displacement is zero.

Hence, the average velocity for the whole episode is 0 m/s

7 0
3 years ago
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A 21.6−g sample of an alloy at 93.00°C is placed into 50.0 g of water at 22.00°C in an insulated coffee-cup calorimeter with a h
IrinaK [193]

Answer : The specific heat capacity of the alloy 1.422J/g^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

C_1 = specific heat of alloy = ?

C_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of alloy = 21.6 g

m_2 = mass of water = 50.0 g

T_f = final temperature of system = 31.10^oC

T_1 = initial temperature of alloy = 93.00^oC

T_2 = initial temperature of water = 22.00^oC

Now put all the given values in the above formula, we get

21.6g\times c_1\times (31.10-93.00)^oC=-50.0g\times 4.18J/g^oC\times (31.10-22.00)^oC

c_1=1.422J/g^oC

Therefore, the specific heat capacity of the alloy 1.422J/g^oC

6 0
3 years ago
A force of 100 N acts on a body and moves at a distance of 2 m in the direction of the force. How much work has been done?
Flauer [41]

Answer:

200 joules

Explanation:

work=force×distance

5 0
3 years ago
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