A low-pressure sodium vapor lamp whose wavelength is 5.89 x 10−7 m passes through double-slits that are 2.0 x 10−4 m apart and p
1 answer:
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It’s me again lol you’re questions are simple the formula is given in the triangle
The answer is C 39 hz
Please look at the attached image below for the explanation
The answer is C 39 hz
Please look at the attached image below for the explanation
Complete question:
A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical energy of the spring–load system is 2.00 J. Find
(a) the force constant of the spring and (b) the amplitude of the motion.
Answer:
(a) the force constant of the spring = 47 N/m
(b) the amplitude of the motion = 0.292 m
Explanation:
Given;
mass of the spring, m = 200g = 0.2 kg
period of oscillation, T = 0.410 s
total mechanical energy of the spring, E = 2 J
The angular speed is calculated as follows;
(a) the force constant of the spring
(b) the amplitude of the motion
E = ¹/₂kA²
2E = kA²
A² = 2E/k
Answer:
E = 1440 kJ
Explanation:
It is given that,
Power of a cooker oven is 800 W
Voltage at which it is operated is 230 V
Time, t = 30 minutes = 1800 seconds
We need to find the electrical energy used by the cooker oven. The product of power and time is equal to the energy consumed. So,
So, electrical energy of 1440 kJ is consumed by the cooker oven.