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dezoksy [38]
3 years ago
12

1) Students set up the apparatus you see here to separate water into its two components: hydrogen and oxygen. The illustration a

lso shows us that hydrogen and oxygen, when uncombined, exist as diatomic molecules. Based on the chemical formula of water, H2O. we would expect twice as many hydrogen bubbles to collect on the negative electrode compared to the number of oxygen bubbles collecting on the positive electrode. Which chemical equation best illustrates how the total number of atoms is conserved during this chemical reaction.
A) 2H2O ⇒ 2H2 + 2O
B) H2O ⇒ 2H + O
C) H2O ⇒ H2 + O2
D) 2H2O ⇒ 2H2 + O2

2) A synthesis reaction combines two or more elements to form a compound. In this case, hydrogen and chlorine have combined to hydrochloric acid or hydrogen chloride. Which equation correctly represents this chemical reaction?
A) 6H2 + 6Cl2 ⇒ 12HCl
B) H2 + Cl2 ⇒ 2HCl
C) 2H + 2Cl ⇒ 2HCl
D) H + Cl ⇒ HCl

2nd image goes with number 2

Chemistry
1 answer:
zvonat [6]3 years ago
8 0

Answer:

1) D; 2) B

Explanation:

1) <em>Conservation of atoms </em>

D is correct.

It has four atoms of H and two of O on each side of the reaction arrow.

A. <em>Wrong</em>. It has the same number of H and O on each side, but it has the <em>wrong product</em>. The reaction forms O₂ molecules, not O atoms.  

B. <em>Wrong</em>. Atoms are balanced, but the <em>products are incorrect</em>.

C. <em>Wrong</em>. Atoms are balanced, but the <em>reactants are incorrect</em>.

===============

2) <em>Chemical equations </em>

B is correct.

The atoms are balanced, and the equation shows the correct formulas of the molecules.

A. <em>Wrong</em>. Atoms are balanced, and the formulas are correct, but the equation is <em>not in its simplest form</em>. The coefficients are not in their lowest terms. We must divide every coefficient by six to get the correct equation: H₂ + Cl₂ ⟶ 2HCl.

C. <em>Wrong</em>. The <em>reactants are incorrect</em>, and the equation is <em>not in its lowest terms</em>.

D. <em>Wrong</em>. The <em>reactants are incorrect</em>.

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Anna71 [15]

Answer:

150.0 mL.

Explanation:

  • It is known that the no. of millimoles of HNO₃ before dilution = the no. of millimoles of HNO₃ after dilution.

∵ (MV) before dilution = (MV) after dilution.

<em>∴ V before dilution = (MV) after dilution / M before dilution</em> = (0.15 M)(500.0 mL)/(0.50 M) = <em>150.0 mL.</em>

7 0
3 years ago
Which compound has the same empirical and molecular formula ethyne ethene ethane methane?
Margaret [11]
Empirical formula is the simplest ratio of whole numbers of components in a compound 
molecular formula is the actual ratio of components in a compound .
the molecular formula for the compounds given are as follows
ethyne  - C₂H₂
ethene - C₂H₄
ethane - C₂H₆
methane - CH₄
the actual ratios of the elements                 simplified ratio
                     C : H                                           C : H
ethyne            2:2                                             1:1
ethene            2:4                                             1:2
ethane            2:6                                             1:3
methane         1:4                                             1:4
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6 0
3 years ago
For 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g), if you begin with 16.00 g ammonia and excess oxygen, how many grams of water will be ob
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8 0
3 years ago
In the decomposition potassium nitride, 10.65 g of nitrogen form. How much potassium nitride was present initially ?
leonid [27]

Answer:

Mass =  99.8 g  

Explanation:

Given data:

Mass of potassium nitride = ?

Mass of nitrogen produced = 10.65 g

Solution:

Chemical equation:

2K₃N→ 6K + N₂

Moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles =  10.65 g / 28 g/mol

Number of moles = 0.38 mol

Now we will compare the moles of nitrogen with potassium nitride.

                        N₂              ;         K₃N

                         1               :            2

                         0.38          :          2×0.38 =0.76

Mass of potassium nitride:

Mass = molar mass × number of moles

Mass =    131.3 g/mol ×   0.76 mol

Mass =  99.8 g    

7 0
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8 0
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