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Gennadij [26K]
4 years ago
7

A beaker containing a mixture of N2(g) and H2(g) is cooled by placing it in a tray of cold water. In response to the cooling, th

e likely number of collisions between the molecules of N2(g) and H2(g) will . The rate of the reaction will .
Chemistry
2 answers:
sashaice [31]4 years ago
5 0

Answer:

A beaker containing a mixture of N2(g) and H2(g) is cooled by placing it in a tray of cold water. In response to the cooling, the likely number of collisions between the molecules of N2(g) and H2(g) will  <em><u>decrease</u></em> . The rate of the reaction will  <em><u>decrease</u></em> .

Explanation:

#platofam

Nataliya [291]4 years ago
3 0

The frequency of collisions between the N₂ and H₂ molecules will decrease and the rate of reaction will also decrease.

Since the water is cooler than the gas mixture, heat will flow from the gas to the water.

The gas will cool down, so the average kinetic energy of the gas molecules will decrease.

The molecules will be moving more slowly, so there will be <em>fewer collisions</em> and <em>fewer of these collisions will have enough energy to react</em>.

The rate of reaction between H₂ and N₂ molecules at room temperature is exceedingly slow, <em>but cooling the gas mixture will make the reaction even slower</em>.

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by having positive and negative ends and stronger intermolecular forces of attraction.

Explanation:

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8 0
2 years ago
Which of the following ways can the volume of a gas be changed, without changing its mass? Select all that apply.
pochemuha

Answer:

It can be spread into a smaller container

It can ve spread out into a larger container

It can be dissolved into a liquid

8 0
3 years ago
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If your going down a hill what type of energy are you making?
kow [346]

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Gravitational potential energy - into Kinetic energy

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6 0
3 years ago
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What is the molecular formula for a compound with a molar mass of 42.08g/mol and an empirical formula of ch2
yan [13]

Answer:

C_3H_6

Explanation:

Hello!

In this case, since the empirical formula is the smallest representation of the molecular formula, it is known that the times in which the empirical formula is into the molecular formula is a whole number and is computed by dividing the molar mass of the molecular formula by that of the empirical formula as shown below:

\frac{42.08g/mol}{12.01+1.01x2}= \frac{42.08g/mol}{14.03g/mol}=3

Thus, the molecular formula times the empirical formula by 3 to obtain:

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3 0
2 years ago
In a beaker, 300 grams of water at 80°C cools down to 20°C. Assume all the heat from the water is absorbed by 100 cubic meters o
scZoUnD [109]

Answer:

mass of water, mw = 300g = 0.3kg

∆Tw = (80 - 20) °C

volume of air, va = 100m³

mass of air, ma = 100g = 0.1kg

∆Ta = ?

H = mc∆T

Hw = mwcw∆Tw

Hw = 0.3*4200*60

Hw = 75600J

Hw = 75.6 kJ

All the above heat energy got absorbed by air,

that is; Ha = 75600J

since it's given that the heat was absorbed by a specific amount of volume of air

then specific capacity of volume of air is

then,

ca = <u>Ha</u><u> </u> × <u>density</u><u> </u>

ma temp

then,

Ha = vaca∆Ta

where, ca = volumetric heat capacity of air = 0.012kJ/m³°C

75.6kJ = 100m³ × 0.012kJ/m³°C × ∆Ta

75.6 = 1.2/°C × ∆Ta

∆Ta = 63°C

63°C is the temperature change in air.

4 0
3 years ago
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