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Gennadij [26K]
3 years ago
7

A beaker containing a mixture of N2(g) and H2(g) is cooled by placing it in a tray of cold water. In response to the cooling, th

e likely number of collisions between the molecules of N2(g) and H2(g) will . The rate of the reaction will .
Chemistry
2 answers:
sashaice [31]3 years ago
5 0

Answer:

A beaker containing a mixture of N2(g) and H2(g) is cooled by placing it in a tray of cold water. In response to the cooling, the likely number of collisions between the molecules of N2(g) and H2(g) will  <em><u>decrease</u></em> . The rate of the reaction will  <em><u>decrease</u></em> .

Explanation:

#platofam

Nataliya [291]3 years ago
3 0

The frequency of collisions between the N₂ and H₂ molecules will decrease and the rate of reaction will also decrease.

Since the water is cooler than the gas mixture, heat will flow from the gas to the water.

The gas will cool down, so the average kinetic energy of the gas molecules will decrease.

The molecules will be moving more slowly, so there will be <em>fewer collisions</em> and <em>fewer of these collisions will have enough energy to react</em>.

The rate of reaction between H₂ and N₂ molecules at room temperature is exceedingly slow, <em>but cooling the gas mixture will make the reaction even slower</em>.

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1) to calculate the limiting reactant you need to pass grams to moles.
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mass of N2O4: 50.0 g 
molar mass of <span>N2O4 = 92.02 g/mol
</span><span>molar mass of N2H4 = 32.05 g/mol.
</span>mass of N2H4:45.0 g

moles N2O4=50.0/92.02 g/mol= 0,54 mol of N2O4
moles N2H4= 45/32.05 g/mol= 1,40 mol of <span><span>N2H4

</span> 2)</span>
By looking at the balanced equation, you can see that 1 mol of N2O4 needs 2 moles of N2H4 to fully react . So to react  0,54 moles of N2O4, you need 2x0,54 moles of <span>N2H4 moles
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3) 1 mol of N2O4 reacting, will produce 3 mol of N2 (look at the equation)
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0,54 mol N2O4--------x
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4) the only thing left to do is convert the moles obtained, to grams.
We use the same formula as before, moles equal to mass divided by molar mass.
moles= \frac{grams}{molar mass}             (molar mass of N2= 28)
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