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baherus [9]
3 years ago
9

An aluminum block has a volume of 30.0 cm³ and a mass of 81 grams. What is the density of aluminum?

Chemistry
1 answer:
kupik [55]3 years ago
4 0

Answer:

Density = 2.7 \ g/cm^3

Explanation:

The equation for density is:

Density = \frac{mass}{volume}

We can plug the given values into the equation:

Density = \frac{81\ g}{30.0\ cm^2}

Density = 2.7 \ g/cm^3

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Consider the malate dehydrogenase reaction from the citric acid cycle. Given the listed concentrations, calculate the free energ
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<u>Answer:</u> The Gibbs free energy of the reaction is 21.32 kJ/mol

<u>Explanation:</u>

The chemical equation follows:

\text{Malate }+NAD^+\rightleftharpoons \text{Oxaloacetate }+NADH

The equation used to Gibbs free energy of the reaction follows:

\Delta G=\Delta G^o+RT\ln K_{eq}

where,

\Delta G = free energy of the reaction

\Delta G^o = standard Gibbs free energy = 29.7 kJ/mol = 29700 J/mol  (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = Temperature = 37^oC=[273+37]K=310K

K_{eq} = Ratio of concentration of products and reactants = \frac{\text{[Oxaloacetate]}[NADH]}{\text{[Malate]}[NAD^+]}

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[NADH]=2.0\times 10^2mM

\text{[Malate]}=1.37mM

[NAD^+]=490mM

Putting values in above expression, we get:

\Delta G=29700J/mol+(8.314J/K.mol\times 310K\times \ln (\frac{0.130\times 2.0\times 10^2}{1.37\times 490}))\\\\\Delta G=21320.7J/mol=21.32kJ/mol

Hence, the Gibbs free energy of the reaction is 21.32 kJ/mol

4 0
3 years ago
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