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baherus [9]
2 years ago
9

An aluminum block has a volume of 30.0 cm³ and a mass of 81 grams. What is the density of aluminum?

Chemistry
1 answer:
kupik [55]2 years ago
4 0

Answer:

Density = 2.7 \ g/cm^3

Explanation:

The equation for density is:

Density = \frac{mass}{volume}

We can plug the given values into the equation:

Density = \frac{81\ g}{30.0\ cm^2}

Density = 2.7 \ g/cm^3

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A sample of gas occupies 280 mL when the pressure is 560.00 mm Hg . If the temperature remains constant , what is the new pressu
vichka [17]

Answer : The new pressure if the volume changes to 560.0 mL is, 280 mmHg

Explanation :

According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = 560.00 mmHg

P_2 = final pressure = ?

V_1 = initial volume = 280 mL

V_2 = final volume = 560.0 mL

Now put all the given values in the above formula, we get:

560.00mmHg\times 280 mL=P_2\times 560.0 mL

P_2=280mmHg

Therefore, the new pressure if the volume changes to 560.0 mL is, 280 mmHg

3 0
3 years ago
In the simulation, open the Custom mode. The beaker will be filled to the 0.50 L mark with a neutral solution. Set the pH to 2.8
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3 0
3 years ago
Can u help me with this
dolphi86 [110]

Answer:

c

Explanation:

the reason is because your a homosiejenenddj

8 0
2 years ago
how many grams of calcium sulfate are produced from 10 grams of calcium nitrate and how many grams of calcium sulfate are produc
AlekseyPX

Answer:  8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Ca(NO_3)_2=\frac{10g}{164g/mol}=0.061moles

\text{Moles of} Li_2SO_4=\frac{10g}{110g/mol}=0.091moles

Ca(NO_3)_2+Li_2SO_4\rightarrow 2LiNO_3+CaSO_4  

According to stoichiometry :

1 mole of Ca(NO_3)_2 require = 1 mole of Li_2SO_4

Thus 0.061 moles of Ca(NO_3)_2 will require=\frac{1}{1}\times 0.061=0.061moles  of Li_2SO_4

Thus Ca(NO_3)_2 is the limiting reagent as it limits the formation of product and Li_2SO_4 is the excess reagent.

As 1 mole of Ca(NO_3)_2 give = 1 mole of CaSO_4

Thus 0.061 moles of Ca(NO_3)_2 give =\frac{1}{1}\times 0.061=0.061moles  of CaSO_4

Mass of CaSO_4=moles\times {\text {Molar mass}}=0.061moles\times 136g/mol=8.30g

Thus 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

6 0
3 years ago
Identify water resevoirs as usuable or unusuable on their current state
kupik [55]
Oceans :unusable
Rivers :usable
Glaciers :usable
Freshwater: usable
Lakes :usable
Groundwater :usable
8 0
3 years ago
Read 2 more answers
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