9514 1404 393
Answer:
b) 31%
Step-by-step explanation:
95% of the normal distribution is between Z values of ±1.96.
99% of the normal distribution is between Z values of ±2.576.
The change from a 95% interval to a 99% interval widens the range by ...
(2.576/1.96 -1) × 100% ≈ 31.4%
The width of the interval increases about 31%.
__
Compare the two attachments. The tail area of 0.05 means the central area is 0.95. Similarly, the tail area of 0.01 means the central area is 0.99.
_____
<em>Additional comment</em>
As always, when you're dealing with percentages, you need to understand what the base value is. Here, when we're talking about 95% and 99% confidence intervals, we're not talking about the numbers 0.95 and 0.99 and the increase from 0.95 to 0.99.
Rather we're talking about areas under the normal probability distribution curve, and the Z-values associated with those intervals. The change in interval width refers to the change in Z-values associated with the areas of 0.95 and 0.99.
1. Mark intersection points of arcs with C and D.
2. Draw perpendicular bisector CD
Answer:
The answer is 180 degrees.
Step-by-step explanation:
The rotation that maps one side to an adjacent side is 360°/6 = 60°. This is the least rotation that plots the regular hexagon to the aforementioned. In the least whole number of these minimum rotations, such as three 60° rotations to make 180°, will retain the hexagon identical.
Please mark me brainliest and have a awesome day! :D