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-Dominant- [34]
3 years ago
7

Find the equation of a line that is perpendicular to y = (1/6)x + 4 and passes through the point (3, 8).

Mathematics
2 answers:
NeX [460]3 years ago
8 0

Answer: y=-6x+26

Step-by-step explanation: We can find the slope of a line that is perpendicular to another line by taking the negated reciprocal of the slope of the original line. So our slope for the perpendicular line is: -6. Now we can put this in a equation to find the y-intercept. So the equation is y=-6x+26

patriot [66]3 years ago
7 0

Answer:

Step-by-step explanation:

Answer: y=26−6x

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Since we have given that

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so, As shown in the figure:

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If CD = 5 ft,

Let,  AB = y, DC = x.

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\tan 60^\circ=\frac{AB}{BC}\\\\\frac{\sqrt{3}}{2}=\frac{y}{x}\\\\x=\frac{y}{\sqrt{3}}

Similarly, in Δ ACD,

\tan 30^\circ=\frac{AB}{BD}\\\\\frac{1}{\sqrt{3}}=\frac{y}{x+5}\\\\\frac{1}{\sqrt{3}}=\frac{y}{\frac{y}{\sqrt{3}}+5}\\\\\frac{1}{\sqrt{3}}=\frac{y\sqrt{3}}{y+5\sqrt{3}}\\\\3y=y+5\sqrt{3}\\\\2y=5\sqrt{3}\\\\y=\frac{5\sqrt{3}}{2}\\\\y=4.33\ ft

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