Answer:
Huh! What does that means?
Step-by-step explanation:
Answer:
Option c.
Step-by-step explanation:
Using the normal curve to approximate a sampling distribution:
For a sample size n and a proportion n, the normal curve can be used if:
and 
Option a:


So option a cannot be used.
Option b:


So option b cannot be used.
Option c:


So option c can be used, and is the answer
Option d:


So option d cannot be used.
The answer is given by option c.
Answer:
7
Step-by-step explanation: (dont trust me)
x^2 + (7)x +18
x(x + 4) + 3(x + 6)
Be E.N.D.bddndmmfmddndnxncnfnd
The question doesn't seem specific enough. If there are options, please list.