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3 years ago

Find the solution for s 9s + 3 = 57

Mathematics

2 answers:

torisob [31]3 years ago

5 0

The solution is 6

9x6+3=57

lutik1710 [3]3 years ago

4 0

You have to subtract the 3 from 57 then divide the 9 from 54 (which you got from subtracting 57 and 3) your answer is s=6

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Differentiate the following equation

Bingel [31]

Answer:

$\frac{dy}{dx} = \frac{4}{1-x}$

Step-by-step explanation:

y = 3 - 4ln(1 - x)

⇒ $\frac{dy}{dx} =3\frac{d}{dx} -4ln(1-x)\frac{d}{dx}$

⇒ $\frac{dy}{dx} =0 -4ln(1-x)\frac{d}{dx}$

⇒ $\frac{dy}{dx} =0 -4(\frac{1}{1-x})\times-1$

⇒ $\frac{dy}{dx} = \frac{4}{1-x}$

4 0

3 years ago

Write in simplest form:<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24a%5E%7B10%7Db%5E%7B6%7D%7D" id="TexFormula1" ti

Charra [1.4K]

Answer:

$2a^3b^2\sqrt[3]{3a}$

Step-by-step explanation:

Use the following rules for exponents:

$a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x$

Simplify 24. Find two factors of 24, one of which should be a perfect cube:

$8*3=24\\\\2^3=8$

Insert:

$\sqrt[3]{2^3*3a^{10}b^6}$

Now split the exponents. Split 10 into as many 3's as possible:

$10=3+3+3+1$

Insert as exponents:

$\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}$

Split 6 into as many 3's as possible:

$6=3+3$

Insert as exponents:

$\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}$

Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):

$2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}$

Simplify:

$2a^3b^2\sqrt[3]{3a}$

:Done

6 0

3 years ago

I need help please this is for math

maxonik [38]

5x + 13 Hope this helps you

8 0

3 years ago

What is the value of x in the equation 1/5 x-2/3 y=30 when y =15

laiz [17]

First replace y with 15.
1/5x-10=30
Then just solve from there.
x=200

4 0

3 years ago

Read 2 more answers

PLEASE HELP ME ON THIS IT IS GEOMETRY PLEASE HELP ME DO NOT WASTE MY ANSWERS PLEASE HELP ME

sweet-ann [11.9K]

It’s hard to tell because there isn’t a visual. My guess is that it’s ASA~ and SAS~ because T is congruent to P and A and F have the same angle

5 0

3 years ago