hii!
n(n-4) = 60
n^2 - 4n - 60 = 0
( n - 10 )(n + 6 ) = 0
n-10 = 0 ---> n = 10 ---> 10*(10-4) = 10*6 = 60
n+6 = 0 --> n = -6 ---> -6 * (-6-4) = -6 * -10 = 60
Answer:
B
Step-by-step explanation:
Expressing the ratios as fractions, that is
= 
( cross- multiply )
a = 3b
= 
( cross- multiply )
c = 5b
------------------------------------------
Given
, substitute values from above for a and c
= 
= 
= 
← cancel b on numerator/ denominator
= 
→ B
How do I find the Q1 and Q3?<br><br>
0,0,1,2,2,3,4,4,4,4,5,6,6,7,7
Angelina_Jolie [31]
Answer:
Q1 = 2
Q3 = 6
Step-by-step explanation:
Mathematically, we have
Q1 = (n + 1)/4 th term
where n is the number of terms
By the count, we have n as 15
Q1 = (15 + 1)/4
Q1 = 4th term
Looking at the arrangement, the 4th term is 2
For Q3
Q3 = 3(n + 1)/4 th term
n = 15
Q3 = 3 * 4 = 12th term
The 12th term is 6
So that is the 3rd quartile
Answer:
if you are asking for a math equation then 2+4+5=11
Step-by-step explanation:
