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3 years ago

HELP QUICK. I WILL THUMBS UP

Mathematics

2 answers:

scoray [572]3 years ago

6 0

Answer:

<h2>Segment AD is 4, and segment AE is 2.</h2>

Step-by-step explanation:

The given triangle is attached.

In this problem we have two proportional triangles. We know that because it can be applied the theorem of Thales, which is about similarities, it describes the ratio between proportional segment, and this happens when we have a pairs of parralles crossed by transversal, as we have here.

So, if AB = 8 and AC = 4, which belong to the bigger triangle. That means the smaller must be in the same ratio, that is, one side must be half the other one. SO, from this proportion we know that if AD = 4, then AE = 2, and this is the statement we would need to prove that DE is half of the length of BC.

Actually, from the given graph and the given values, we already know that the ratio of this proportional figures is 1/2.

Therefore, the right answer is "Segment AD is 4, and segment AE is 2", because it represents the same proportion that the given one, and gives the proportion we want to find.

Ugo [173]3 years ago

5 0

A diagram would be nice. The quick answer is C.

The first answer makes AE 8 which is twice as long as AC. I don't think the intent of the question is to use an external point.

The second one is also incorrect. This time E is in a place such that it makes AC and AE both equal and that too isn't possible.

The third one is the answer because D and E are both 1/2 the distance between the end point of the line containing them.

D is wrong because E is the midpoint of AC but D is not the midpoint of AB.

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Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p

zubka84 [21]

Answer: The required answers are

(a) 0.25, (b) 0.62, (c) 6.

Step-by-step explanation: Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

$P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.$

(a) The probability of getting 5 heads is given by

$P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.$

(b) The probability of getting 5 or more than 5 heads is

$P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.$

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

$P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.$

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

3 0

3 years ago

On a road trip,drove at a speed of 60 miles per hour for the first two hours. She then increased her speed by 25%. How fast was

love history [14]

This can either be done by multiplying with 125% (1.25) or, by dividing by dividing on 4 and adding a part.

This is the easiest way, tho.

60*1.25=75

The correct answer is 75 mph.

4 0

3 years ago

Read 2 more answers

What is the answer to <br> 5x+15<-10

MatroZZZ [7]

Answer:

x<-5

Step-by-step explanation:

Subtract 15 from both sides, divide both sides by 5

5 0

3 years ago

Read 2 more answers