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3 years ago

Which expression is equivalent to 4^-5?

2 answers:

7 0

Since there is a negative exponent, you need to first convert that into a positive exponent which is going to be 1/4^5
Then, we can find out the answer by simply breaking apart the exponents into 5 groups of 4.
1/(4)(4)(4)(4)(4)
Answer: B

vodka [1.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

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P•3 then add 1/6 of the amount

Black_prince [1.1K]

3*P + (1/6%* 3p)=

Thats the formula

basically its: 3 * p + 1/6 of 3p

6 0

3 years ago

Find the point of the intersection for the given systems y=x^2+1 and y=x+1

mario62 [17]

set them equal to each other

x²+1=x+1

minus 1 from both sides

x²=x

minus x both sides

x²-x=0

factor

x(x-1)=0

set each to 0

x=0

x-1=0

x=1

subsitute back to find y values

y=x+1, y=0+1, y=1, one point is (0,1)

y=x+1, y=1+1, y=2, another point is (1,2)

the 2 points of intersection are (0,1) and (1,2)

7 0

3 years ago

 (6 pts) The average age of CEOs is 56 years. Assume the variable is normally distributed. If the SD is four years, find the pr

Alenkinab [10]

Answer:

The probability that the age of a randomly selected CEO will be between 50 and 55 years old is 0.334.

Step-by-step explanation:

We have a normal distribution with mean=56 years and s.d.=4 years.

We have to calculate the probability that a randomly selected CEO have an age between 50 and 55.

We have to calculate the z-value for 50 and 55.

For x=50:

$z=\frac{x-\mu}{\sigma}=\frac{50-56}{4}=\frac{-6}{4}= -1.5$

For x=55:

$z=\frac{x-\mu}{\sigma}=\frac{55-56}{4}=\frac{-1}{4}=-0.25$

The probability of being between 50 and 55 years is equal to the difference between the probability of being under 55 years and the probability of being under 50 years:

$P(50$

5 0

3 years ago

Type the correct answer in the box. Rewrite the quadratic equation in the form y = a(x − h)2 + k. y=5x^2-30x+95

S_A_V [24]

Answer:

y = 5(x - 3)^2 + 50

Step-by-step explanation:

The problem wants you to rewrite the quadratic equation in the vertex form y = a(x - h)^2 + k

You are given a quadratic equation in standard form (ax^2 + bx = c).

To convert from standard form to vertex form, there are two ways but I will show you the easier(?) way.

Use the formula x = -b/2a to find the x-value (h) of the vertex. Note that the vertex in "vertex form" is (h, k) which is virtually the same as (x, y).

In y = 5x^2 - 30x + 95, a = 5, b = -30, and c = 95. Substitute a and b into the formula -b/2a.