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2 years ago

Elliot has a collection of 20 toy cars. Will he be able to put an equal number of toy cars on 3 shelves

Mathematics

1 answer:

Yakvenalex [24]2 years ago

6 0

No the closest he can go is 18

You might be interested in

This grid follows two rules.

fredd [130]

Answer:

a = 4,

b = 12

c = 10

d = 15

Step-by-step explanation:

Since the product of each column is equal, therefore,

b*5 = 60

b = 60 ÷ 5 = 12

c*6 = 60

c = 60 ÷ 6 = 10

Since the sum of each column are equal, therefore,

12 + 10 + a = 5 + 6 + d

22 + a = 11 + d

Think of a number you can add to 22, and another number you can add to 11, which will make both sides equal. Add both numbers, whenmultiplied together should give you 60.

Factors of 60 are:

(a, d)

(1, 60) => 22 + a = 11 + d => 22+1 = 11+60 (incorrect)

(2, 30) => 22 + a = 11 + d => 22+2 = 11+30 (incorrect)

(3, 20) => 22 + a = 11 + d => 22+3 = 21+20 (incorrect)

(4, 15) => 22 + a = 11 + d => 22+4 = 11+15 => 26 = 26 [CORRECT]

(5, 12) => 22 + a = 11 + d => 22+5 = 11+12 (incorrect)

(6, 10) => 22 + a = 11 + d => 22+6 = 11+10 (incorrect)

Therefore,

a = 4,

d = 15

6 0

3 years ago

Which side lengths could create a triangle??

azamat

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

anyone know thus multiple question.... yes you , i know you've saw this , your reading now ... please help (if you can of course

Kitty [74]

Answer:

if union, U means plus,+

if intersect means minus, -

6 0

3 years ago

Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil

andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that $p = 0.26$

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that $n = 5$

4 failures, so 1 success, and we have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898$

0.3898 = 38.98% probability that there will be 4 failures

4 0

2 years ago

Need help again...<br> :(

agasfer [191]

Answer:

Step-by-step explanation:

I think your suppose to find the greatest common factor

5 0

3 years ago