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zysi [14]
3 years ago
15

Find the area of the figure to the nearest tenth.

Mathematics
1 answer:
jenyasd209 [6]3 years ago
3 0

Answer:

99.0 in²

Step-by-step explanation:

The area (A) of the sector of the circle is calculated as

A = area of circle × fraction of circle

  = πr² × \frac{140}{360} ( where r is the radius )

Here r = 9, thus

A = π × 9² × \frac{14}{36}

   = 81π × \frac{14}{36} ≈ 99.0 in²

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Answer:

7 gallons per minute

Step-by-step explanation:

315/45 = 7

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3 years ago
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Amir walks 1/2 mile in 15 minutes. Jody walks 2/3 mile in 20 minutes. Who walks at a faster rate?
ella [17]

Answer:

Jody walks at a faster rate because it would take Amir 30 minutes to walk a mile and Jody approximately 26.6 minutes to walk a mile.

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2 years ago
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Solve the system! <br> - 3x + 3y = 4<br> y=x+3<br> What is the solution?
STatiana [176]

Answer:

This system has no solution

Step-by-step explanation:

If this is the real question,it has no solution

3 0
1 year ago
Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the
maksim [4K]

Answer:

The line of symmetry is x = -3

Explanation:

Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

y=ax^2+bx+c

The line of symmetry coincides with the x-axis of the vertex. To find the x-coordinate of the vertex, we can use the formula:

x_v=-\frac{b}{2a}

In this problem, we have:

y=-x^2-6x-13

Then:

a = -1

b = -6

We write now:

x_v=-\frac{-6}{2(-1)}=-\frac{-6}{-2}=-\frac{6}{2}=-3

Part 3:

For this part, we need to find the x-intercepts. This is, when y = 0:

-x^2-6x-13=0

To solve this, we can use the quadratic formula:

x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}

And solve:

x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

y=-0^2-6\cdot0-13=-13

The y-intercept is at (0, -13)

Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

x=1\Rightarrow y=-1^2-6\cdot1-13=-1-6-13=-20x=-1\Rightarrow y=-(-1)^2-6\cdot(-1)-13=-1+6-13=-8

The two points are:

(1, -20)

(-1, -8)

Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

The third could be the vertex. We need to find the y-coordinate of the vertex. We know that the x-coordinate of the vertex is x = -3

Then, y-coordinate of the vertex is:

y=-(-3)^2-6(-3)-13=-9+18-13=-4

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

8 0
1 year ago
Evaluate the expression -434 + (-1.5)2
lorasvet [3.4K]

Answer: -437

Step-by-step explanation:

5 0
3 years ago
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