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castortr0y [4]
2 years ago
8

Find the difference: square root of 20 - square root of 80

Mathematics
2 answers:
Mamont248 [21]2 years ago
8 0

Answer:

-2\sqrt{5}

Step-by-step explanation:

\sqrt{20} = \sqrt{10*2} = \sqrt{5 * 2 *2} = \sqrt{2^2 * 5} = 2\sqrt{5}   \\\\\sqrt{80} = \sqrt{20*4} = \sqrt{5*4 *4} = \sqrt{4^2 * 5} = 4\sqrt{5}   \\\\2\sqrt{5} - 4\sqrt{5} = -2\sqrt{5}

Volgvan2 years ago
5 0

Answer:

b

Step-by-step explanation:

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Lana runs a business where she fixes bikes. She charges $15.75 per hour for her labor as well as a $25 flat fee for any parts sh
Masja [62]

Answer:

y = 15.75x + 25 is the linear equation

$88 would be the total cost

Step-by-step explanation:

First, create the equation using y = mx + b, where x is the number of hours:

y = 15.75x + 25 will be the equation, since the charge is $15.75 per hour and the flat fee is $25

There are 4 hours in between 8:30 AM and 12:30 PM, so to find the cost, plug in 4 as x and simplify:

y = 15.75x + 25

Plug in 4 as x:

y = 15.75(4) + 25

y = 63 + 25

y = 88

So, the total cost would be $88

8 0
2 years ago
On Monday you sent x number of text messages. On Tuesday you sent twice as many. On Wednesday you sent 12 more texts than you se
Lady bird [3.3K]

Answer:

Expression representing number of text messages sent on Tuesday = 2x , where x = text messages sent on Monday

Step-by-step explanation:

Let number of messages sent on Monday = x

So, number if messages sent on Tuesday = 2 times x = 2x

Number of texts sent on Wednesday = 12 more than texts sent on Tuesday = 2x + 12

Number of texts sent on Thursday = Half the texts sent on Wednesday =   1/2 (2x + 12) = x + 6

3 0
3 years ago
Read 2 more answers
Please help someone ​
Cerrena [4.2K]
37 because theres 32 plus 5 which makes it 37
5 0
3 years ago
4w+5z=30 solve for w
zepelin [54]

Answer:

w=\frac{30-5z}{4}

Step-by-step explanation:

4w+5z=30\\\\4w+5z-5z=30-5z\\\\4w=30-5z\\\\\frac{4w=30-5z}{4}\\\\\boxed{w=\frac{30-5z}{4}}

Hope this helps.

3 0
3 years ago
Find the derivative of f(x) = (1 + 6x2)(x − x2) in two ways.
ipn [44]
Using product rule;

f(x)=(1+6x²)(x-x²)

f'(x)=(12x)(x-x²) + (1-2x)(1+6x²) = 12x² -12x³ +1 +6x² -2x -12x³ = -24x³ +18x² -2x +1

Solving the bracket first;

f(x)=(1+6x²)(x-x²) = x -x² +6x³ -6x^4

f'(x)= 1 -2x +18x² -24x³ = -24x³ +18x² -2x +1

3 0
3 years ago
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