(2,-1) x - 2y = 4 3x + y = 6 Determine if the coordinate is a solution to the equations.

Mathematics

1 answer:

ad-work [718]3 years ago

3 0

Answer:

While the coordinates would be a solution to the first equation, they are not for the second equation, so the answer to your question is no.

Step-by-step explanation:

All you have to do is substitute the coordinates into the x and y values.

(2)-2(-1) = 2+2 = 4 We can tell that the coordinates worked for the first equation. Lets see if it works for the second, as well.

3(2) + (-1) = 6-1 = 5 Unfortunately, the coordinates were incorrect for the second equation.

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Cameron is older than Hassan. Their ages are consecutive integers. Find Cameron's

Alexxandr [17]

Answer:

Step-by-step explanation:

So consecutive integers, just means they're separated by a value of 1. This can be generally expressed as "a, a+1" where these two values would be consecutive integers assuming "a" is an integer.

So let's express Hassan's age as the variable "x", since it's unknown. Since Cameron is older, and by definition of a consecutive integer, Cameron's can be expressed as "x+1"

So the equation we need to set up is Cameron's age + 5(Hassan's age) = 145

So we can substitute the variables we defined to express Cameron and Hassan's age: $(x+1) + 5(x) = 145$

Distribute the 5: $x+1+5x$

Add like terms: $6x+1 = 145$

Subtract 1 from both sides: $6x=144$

Divide both sides by 6: $x=24$

Since we used "x" to represent Hassan's age, Hassan's age is 24. Since we used "x+1" to represent Cameron's age, Cameron's age is "24+1" which is just 25

6 0

1 year ago

Find the distance between (-5,6)and (3,2).

skad [1K]

Answer:

$\displaystyle d = 4\sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formulas]: $\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}$
[Distance] [√Radical] (Parenthesis) Add/Subtract: $\displaystyle d = \sqrt{(8)^2+(-4)^2}$
[Distance] [√Radical] Evaluate exponents: $\displaystyle d = \sqrt{64+16}$
[Distance] [√Radical] Add: $\displaystyle d = \sqrt{80}$
[Distance] [√Radical] Simplify: $\displaystyle d = 4\sqrt{5}$