Answer:
c^5 *d^5
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
2^3 is two cubed ...now multiply times 7
<u>7 * 2^3 </u>
Answer: imgurl=http%3A%2F%2Fwww.rasmus.is%2FIS%2FT%2FF%2FSu52k03_m01.gif&imgrefurl=http%3A%2F%2Fwww.rasmus.is%2Fuk%2Ft%2FF%2FSu52k03.htm&tbnid=0mYNOM8hE-8CkM&vet=12ahUKEwj4y9mb3NrvAhXNtFMKHZ9kCDEQMygIegUIARCjAQ..i&docid=Iv4G7-Ojzx0JrM&w=290&h=247&q=Which%20function%20does%20the%20graph%20represent%3F3%2C%2015)Of(x)%20%3D%20(x%20%2B%203)(x%20%2B%207)O%20f(x)%20%3D%20(x%20-%203)(x%20-%207)O%20f(x)%20%3D%203(x%20%E2%80%93%203)(x%20%E2%80%93%207)Of(x)%20%3D%2011(x%20%2B%203)(x%20%2B%207)&safe=active&ved=2ahUKEwj4y9mb3NrvAhXNtFMKHZ9kCDEQMygIegUIARCjAQ
Since this is a fairly small equation, it's pretty easy to plug in a few points to get ordered pairs and sketch a graph:
when x = 0...
f(0) = 2(0)^2
f(0) = 0
(0, 0)
when x = 1...
f(1) = 2(1)^2
f(1) = 2
(1, 2)
when x = -1...
f(-1) = 2(-1)^2
f(-1) = 2
(-1, 2)
from there, you can get a rough sketch of the graph just by plotting those points. essentially, it just looks "skinnier" than your typical parabola because the 2 out front makes the curve steeper.
