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Nikitich [7]
3 years ago
11

Liz had attended class everyday since she started school as a kindergartener. She said she had been in school for about a thousa

nd days what could the actual number of school days be if she rounded to the nearest ten?
Mathematics
2 answers:
Nutka1998 [239]3 years ago
6 0
The answer to your question is 710
nika2105 [10]3 years ago
3 0
This would mean that she has been in school for about 1,000 days. Thus, we need to figure out the amount of days she would have went to school within the week. This would normally be 5 days within the 7. 

5/100 x 1000 is 714.28

When rounded to the nearest ten, it would end up at 710.
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Find an equation in rectangular coordinates for the spherical equation ρ = 7 csc ( ϕ ) csc ( θ )
irinina [24]
\rho=7\csc\phi\csc\theta\implies\rho\sin\phi\sin\theta=7\iff y=7
7 0
3 years ago
Ummm what this ?? Helping my sister
Radda [10]

Answer:

ok this the answer   By definition, a rectangle is a parallelogram because its pairs of opposite sides are parallel. A rectangle also has the special characteristic that all of its angles are right angles; all four of its angles are congruent. The other special case of a parallelogram is a special type of rectangle, a square.

Step-by-step explanation:

6 0
2 years ago
Solve the equation using square roots. x2 + 5 = 41
Stells [14]
X*2 +5 =41
Subtract 5 from both sides
X*2=36

Square root of 36 is 6

X=6

Solve

6*2+5 =41
This’s correct!
3 0
2 years ago
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What is the final concentration if a saline solution consisting of 20% NaCl is diluted using a 1/4 solution?
vodomira [7]

Answer: C.V=C1.V1 +C2.V2

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6 0
3 years ago
Question 4 options: Find the mean and standard deviation for a binomial distribution with 680 trials and a probability of succes
lys-0071 [83]

Answer:

Mean for a binomial distribution = 374

Standard deviation for a binomial distribution = 12.97

Step-by-step explanation:

We are given a binomial distribution with 680 trials and a probability of success of 0.55.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 680 trials

            r = number of success  

           p = probability of success which in our question is 0.55

So, it means X <em>~ </em>Binom(n=680, p=0.55)

<em><u>Now, we have to find the mean and standard deviation of the given binomial distribution.</u></em>

  • Mean of Binomial Distribution is given by;

                    E(X) = n \times p

       So, E(X) = 680 \times 0.55 = 374

  • Standard deviation of Binomial Distribution is given by;

                   S.D.(X) = \sqrt{n \times p \times (1-p)}

                               = \sqrt{680 \times 0.55 \times (1-0.55)}

                               = \sqrt{680 \times 0.55 \times 0.45} = 12.97

Therefore, Mean and standard deviation for binomial distribution is 374 and 12.97 respectively.

3 0
3 years ago
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