Answer:
They should operate Mine 1 for 1 hour and Mine 2 for 3 hours to meet the contractual obligations and minimize cost.
Explanation:
The formulation of the linear programming is:
Objective function:
Restrictions:
- High-grade ore: 
- Medium-grade ore: 
- Low-grade ore: 
- No negative hours: 
We start graphing the restrictions in a M1-M2 plane.
In the figure attached, we have the feasible region, where all the restrictions are validated, and the four points of intersection of 2 restrictions.
In one of this four points lies the minimum cost.
Graphically, we can graph the cost function over this feasible region, with different cost levels. When the line cost intersects one of the four points with the lowest level of cost, this is the optimum combination.
(NOTE: it is best to start with a low guessing of the cost and going up until it reaches one point in the feasible region).
The solution is for the point (M1=1, M2=3), with a cost of C=$680.
The cost function graph is attached.
Answer:
Annual depreciation (year 1)= $1,400
Explanation:
Giving the following information:
Buying price= $36,000.
Useful units= 300,000 units of product.
Salvage value= $6,000
During its first year, the machine produces 14,000 units of product.
To calculate the depreciation expense for the first year under the units of production method, we need to use the following formula:
Annual depreciation= [(original cost - salvage value)/useful life of production in units]*units produced
Annual depreciation= [(36,000 - 6,000)/300,000]*14,000
Annual depreciation= 0.1*14,000= $1,400
Answer:
b. $.66
Explanation:
The computation of the per share value for the one year is
Given that
Current Price = $43
Possible Prices = $42 and $46
Now
u = [($46 - $43) ÷ $43] + 1
= 1.06977
And
d = 1 - [($42 - $43) ÷ $43]
= 0.9767
And,
Risk-Free Rate = T-Bill Rate = Rf = 4.1 %
Now the up move price probability is
= [(1 + Rf) - d] ÷ [u - d]
= [(1.041) - 0.9767] ÷ [1.06977 - 0.9767]
= 0.69088
And,
Exercise Price = $ 45
Now
If the Price is $42, so Payoff = $0
And
if the Price is $46, so Payoff =is
= ($46 - $45)
= $1
Finally the call price is
= [0.69088 × 1 + (1 - 0.69088) × 0] ÷ 1.041
= $0.66367
= $0.66
