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fiasKO [112]
3 years ago
15

Find The Perimeter please asap

Mathematics
1 answer:
nevsk [136]3 years ago
8 0

Answer:

44

Step-by-step explanation:

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Find The derivative of:(cosx/1+sinx)^3​
forsale [732]

Answer:

-\frac{3 \cdot cos^2x}{(1+sinx)^3}

Step-by-step explanation:

y = (\frac{cosx}{1+sinx})^3\\\\\frac{dy}{dx} = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{dy}{dx}(\frac{cosx}{1+sinx})                        [ y = x^n\  \  \ =>  \  \  \  \frac{dy}{dx} = b \cdot x^{n-1} \ ]

    = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{(1+sin x(-sinx) - cosx(cosx)}{(1+sinx)^2}\\\\     [\ \frac{u}{v} = \frac{v \dcot u'- u \cdot v'}{v^2}\ ]

    = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-sin^2x- cos^2x}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x- (sin^2x+ cos^2x)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-1}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1 \cdot(sin x+1)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1}{(1+sinx)}\\\\

   = -3 \cdot \frac{cos^2x}{(1+sinx)^3}

   

5 0
3 years ago
The store is offering 15% discount. The regular price of a T shirt is $23 , what is the discount?
Marina CMI [18]

Answer:

$3.45

Step-by-step explanation:

15% of 23 is 3.45

4 0
3 years ago
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What goes up but never comes down?
zepelin [54]

Answer:

your age and student debt

Step-by-step explanation:

6 0
2 years ago
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For each of the values of h given, when x is increased from 1 to 1+h, work out:
borishaifa [10]
<span>This exercise should show you that as h approaches zero you get the value of the derivative of x^2 at x=1.

</span><span>the change in x^2) / h
   h=1___
   h=.1____
   h=0.1_____
   h=.001___
</span>
<span>change in x^2 = (1+h)^2 - 1^2 = (1+h)^2 - 1</span>
5 0
3 years ago
Write a value that makes 3 &gt; x true How do you<br> know?
Vera_Pavlovna [14]

Answer:

3 > x

x=2

because 3 is larger than 2

Step-by-step explanation:

5 0
3 years ago
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