A car is initially travelling at 12.1m/s It accelerates at a rate of -3.9m/s^2 for 7 seconds. What is it’s final velocity?
1 answer:
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To solve this problem we will use the concepts related to energy conservation. Both potential energy, such as rotational and linear kinetic energy, must be conserved, and the gain in kinetic energy must be proportional to the loss in potential energy and vice versa. This is mathematically
Where,
m = mass
v = Tangential Velocity
= Angular velocity
I = Moment of Inertia
g = Gravity
Replacing the value of Inertia in a Disk and rearranging to find h, we have
Replacing,
Therefore the height of the inclined plane is 5.6m
Answer:
The tension experienced in the string at the highest point is approximately 9.019 Newtons
Explanation:
The mass of the body tied to the string, m = 0.1 kg
The path of motion of the mass = Vertical circular motion
The speed of rotation of the stone, v = 10 m/s
The radius of the circular motion path, r = 1 m
The required information = The tension at the highest point, T
At the highest point, the tension, 'T', comprises of the centrifugal force, 'F', acting upwards in the string and the weight, 'W' of the body acting downwards
∴ T = F - W
Weight, W = m × g
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore;
The centrifugal force, F = 0.1 kg × (10 m/s)²/(1 m) = 10 N
The weight of the mass tied to the string, W ≈ 0.1 kg × 9.81 m/s² = 0.981 N
From which we have;
T = 10 N - 0.981 N = 9.019 N
The tension experienced in the string at the highest point ≈ 9.019 Newtons