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2 years ago

Is this right I'm not sure

Physics

2 answers:

Mariulka [41]2 years ago

8 0

Yes it. Is so good job

Lerok [7]2 years ago

7 0

All except #12 are marked correctly. I'd say you've got this subject mastered !

For #12, I think there's a mistake in the sheet. None of the 4 choices is a correct answer to that one.

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A thin, circular coil of wire of radius r consists of 100 turns of wire carrying a conventional current of I in the counter-cloc

CaHeK987 [17]

Answer:

Magnitude = B = (μ₀*N*I /2R)

Direction= The direction of the magnetic field will be find out by the right hand rule. We will curve the finger of right hand in the direction of the current and our thumb will show the direction of the magnetic field. which will be out of the screen. That is + z direction.

3 0

3 years ago

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A wheel with radius 36 cm is rotating at a rate of 19 rev/s.(a) What is the angular speed in radians per second? rad/s(b) In a t

Sedaia [141]

(a) 119.3 rad/s

The angular speed of the wheel is

$\omega= 19 rev/s$

we need to convert it into radiands per second. We know that

$1 rev = 2 \pi rad$

Therefore, we just need to multiply the angular speed of the wheel by this factor, to get the angular speed in rad/s:

$\omega = 19 rev/s \cdot (2\pi rad/rev))=119.3 rad/s$

(b) 596.5 rad

The angular displacement of the wheel in a time interval t is given by

$\theta= \omega t$

where

$\omega=119.3 rad$

and

t = 5 s is the time interval

Substituting numbers into the equation, we find

$\theta=(119.3 rad/s)(5 s)=596.5 rad$

(c) 127.3 rad/s

At t=10 s, the angular speed begins to increase with an angular acceleration of

$\alpha = 1.6 rad/s^2$

So the final angular speed will be given by

$\omega_f = \omega_i + \alpha \Delta t$

where

$\omega_i = 119.3 rad/s$ is the initial angular speed

$\alpha = 1.6 rad/s^2$ is the angular acceleration

$\Delta t = 15 s - 10 s = 5 s$ is the time interval

Solving the equation,

$\omega_f = (119.3 rad/s) + (1.6 rad/s^2)(5 s)=127.3 rad/s$

(d) 616.5 rad

The angle through which the wheel has rotated during this time interval is given by

$\theta = \omega_i \Delta t + \frac{1}{2} \alpha (\Delta t)^2$

Substituting the numbers into the equation, we find

$\theta = (119.3 rad/s)(5 s) + \frac{1}{2} (1.6 rad/s^2) (5 s)^2=616.5 rad$

(e) 222 m

The instantaneous speed of the center of the wheel is given by

$v_{CM} = \omega R$ (1)

where

$\omega$ is the average angular velocity of the wheel during the time t=10 s and t=15 s, and it is given by

$\omega=\frac{\omega_i + \omega_f}{2}=\frac{127.3 rad/s+119.3 rad/s}{2}=123.3 rad/s$

and

R = 36 cm = 0.36 m is the radius of the wheel

Substituting into (1),

$v_{CM}=(123.3 rad/s)(0.36 m)=44.4 m/s$

And so the displacement of the center of the wheel will be

$d=v_{CM} t = (44.4 m/s)(5 s)=222 m$

8 0

2 years ago

Please solve it ,,,,,,,,,,................................

fredd [130]

Answer:

the distance covered by the body in 5th second =u+a(n- 1/2)=7+4(5- 1/2)

=7+4×9/2

=7+18

=25m

6 0

2 years ago

POTENTIAL I KINETIC ENERGY

TEA [102]

7kinetic energy is decreasing in B

4 0

1 year ago

A man inside the water seea a fish in water. will the fish appear to man in it's actual position? will the man appear to fish in

weqwewe [10]

Answer:

Explanation:

due to the refraction of light,meaning bending of light when it passes from diffrent mediums with diffrent densities

(probably mot the complete ans but smtg like this)

4 0

3 years ago

Read 2 more answers