Answer:
Part a)
Part b)
Explanation:
Part a)
As we know that initially the two blocks are connected by a spring and initially stretched by some amount
Since the two blocks are at rest initially so its initial momentum is zero
since there is no external force on this system so final momentum is also zero
now for initial position the speed is zero
now we have
Part b)
now for ratio of kinetic energy we know that the relation between kinetic energy and momentum is given as
now for the ratio of energy we have
since we know that momentum of two blocks are equal in magnitude so we have
now we have
Answer:
6.78 X 10³ N/C
Explanation:
Electric field near a charged infinite plate
= surface charge density / 2ε₀
Field will be perpendicular to the surface of the plate for both the charge density and direction of field will be same so they will add up.
Field due to charge density of +95.0 nC/m2
E₁ = 95 x 10⁻⁹ / 2 ε₀
Field due to charge density of -25.0 nC/m2
E₂ = 25 x 10⁻⁹ / 2ε₀
Total field
E = E₁ + E₂
= 95 x 10⁻⁹ / 2 ε₀ + 25 x 10⁻⁹ / 2ε₀
= 6.78 X 10³ N/C
Answer:
92.81 psia.
Explanation:
The density of water by multiplying its specific gravity by the density of sea water.
SG = density of sea water/density of water
ρ = SG x ρw
1 kg/m3 = 62.4 lbm/ft^3
= 1.03 * 62.4
= 64.27lbm/ft^3.
The absolute pressure at 175 ft below sea level as this is the location of the submarine.
P = Patm +ρgh
= 14.7 + 64.27 * 32.2 * 175
Converting to pound force square inch,
= 14.7 + 64.27 * (32.2ft/s^2) * (175ft) * (1lbf/32.2lbm⋅ft/s^2) * (1ft^2/144in^2 )
= 14.7 + 78.11 psia
= 92.81 psia.
