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Colt1911 [192]
3 years ago
9

The electric potential difference across the membrane of a body cell is 0.070 V (higher on the outside than on the inside). The

cell membrane is 8.0 x 10-9 m thick. Determine the magnitude and direction of the E field through the cell membrane. Describe any assumptions you made
Physics
1 answer:
12345 [234]3 years ago
5 0

Answer:

The electric field is 8.75 \times 10^{6}~v~m^{-1} and the ditection is from outer to inner side of the membrane.

Explanation:

We know the electric field (\vec{E}) is given by \vec{E} = - \nabla V, 'V' being the potential.

In 1-D, it can be written as

E=\dfrac{V}{d}

where 'd' is the separation of space in between the potential difference is created.

Given, V = 0.070~V~ and the thickness of the cell membrane is d = 8.0 \times 10^{-9}~m.

Therefore the created electric field through the cell membrane is

E = \dfrac{0.07~V}{8 \times 10^{-9}~m} = 8.75 \times 10^{6}~m~s^{-1}

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Which unit is equivalent to j/s
mrs_skeptik [129]

To be honest, there's no sure way to answer that, because you haven't defined your terms and we can't be sure of what j or s might be.

Tell you what I'll do:. I'll assume definitions for j and s, and then I'll answer the question that I invented.

Assume that j stands for Joule, the unit of energy. And assume that s stands for 'second', the unit of time.

Then j/s is the rate of transferring energy or doing work.

Its unit is the Watt, equivalent to 1 Joule per second.

In your system of notation, it would be 'w' .

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3 years ago
Kahalagahan ng diagram​
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  • <em>m</em><em>ahalaga ito upang mas mapaliwanag mo ng maayos at klaro ang isang bagay o pangyayari.</em>

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3 years ago
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Light year is a unit of?
IrinaVladis [17]
Light year is the unit of distance. It is the distance that an object travels in one year with the speed of light.

In short, Your Answer would be "Distance"

Hope this helps!
3 0
3 years ago
If the lily pads are spaced 2.4 m apart and Ferdinand jumps with a speed of 5 m/s taking 0.6 s to go from lily pad to lily pad,
Zina [86]

Answer:

36.87^{\circ}

Explanation:

v = Velocity of Ferdinand = 5 m/s

\theta = Angle of jump

T = Time taken = 0.6 s

R = Distance between lily pads = 2.4 m

Horizontal range is given by

R=v_xT\\\Rightarrow R=vcos\theta T\\\Rightarrow cos\theta=\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{2.4}{5\times 0.6}\\\Rightarrow \theta=36.87^{\circ}

The angle at which Ferdinand make each of his jumps is 36.87^{\circ}

8 0
3 years ago
oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student
12345 [234]

Answer:

Mass, m = 6.18 kg

Explanation:

Given the following data;

Frequency, F = 10 Hz

Spring constant, k = 250 N/m

We know that pie, π = 22/7

To find the mass, we would use the following formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

m is the mass of the spring.

Substituting into the formula, we have;

10 = 1/2 * 22/7 * √250/m

10 = 22/14 * √250/m

Cross-multiplying, we have;

140 = 22 * √250/m

Dividing both sides by 22, we have;

140/22 = √250/m

6.36 = √250/m

Taking the square of both sides, we have;

6.36² = (√250/m)²

40.45 = 250/m

Cross-multiplying, we have;

40.45m = 250

Mass, m = 250/40.45

Mass, m = 6.18 kg

3 0
3 years ago
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