Add 4
.. 5e^(2x) = 15
Divide by 5
.. e^(2x) = 3
Take the natural log
.. 2x = ln(3)
Divide by 2
.. x = ln(3)/2 . . . . . . . . . corresponds to the 3rd selection
289 196 248 379 319 276 198 349
(in order) 196, 198, 248, 276, 289, 319, 349, 379 there are eight numbers.
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196, 198, 248, 276
since the median is between 198 and 248, we must add both numbers together and divide them by two:
(198 + 248) ÷ 2
= 446/2
<h2>
= 223 (first quartile)</h2>
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289, 319, 349, 379
since the median is between 319 and 349, we must add both numbers together and divide them by two:
(319 + 349) ÷ 2
= 668/2
<h2>
= 334 (third quartile)</h2>
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Interquartile range:
<h2>
IQR: 334 - 223 = 111 </h2>
<em>I double-checked my answers btw</em>
We know that
the equation of a circle is
(x-h+(y-k)²=r²
where (k,k)----> is the center
and
r----> is the radius
y²+2x+x²-24y= -120
Group
terms that contain the same variable
(y²-24y)+(x²+2x)=-120
Complete
the square twice. Remember to balance the equation by adding the same constants
to each side
(y²-24y+144)+(x²+2x+1)=-120+144+1
<span>Rewrite as perfect squares</span>
(y-12)²+(x+1)²=25
(x+1)²+(y-12)²=5²
the answer isthe coordinates of the center are (-1,12)the radius is 5 units
