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zepelin [54]
3 years ago
12

"Find the value of x. Round to the nearest tenth. Refer to the attachment below. "

Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0
Use\ \cos.\\\\\cos24^o=\dfrac{11}{x}\\\\\cos24^o\approx0.9135\\\\\dfrac{11}{x}\approx0.9135\ \ \ |cross\ multiply\\\\0.9135x\approx11\ \ \ \ |divide\ both\ sides\ by\ 0.9135\\\\x\approx12
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How would you solve this problem 999 + 587 = 1000 + what = what ? How would this problem be solved
bija089 [108]

Answer:

2,586

Step-by-step explanation:

Add 1000+1000

2000

Since its 999 not 1000 subtract 1

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Now add 1 and subtract 1 from 587

Then add 2000 with 586

2,586

3 0
3 years ago
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Just click the picture you don't have to show your work. IF you want to you can tho.
weeeeeb [17]
The correct answer is A.

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8 0
3 years ago
John buys 3 pounds of cherries and 2 pounds of bananas he pays a total of $24.95 the bananas cost $6.50 less per pound than the
Murrr4er [49]

John will pay $8.68 for the combined cost of 1 pound of banana and 1 pound of cherries.

Let: b=cost of banana per pound and c=cost of cherries per pound

Equation 1: For 3 pounds of cherries and 2 pounds of bananas, John pays a total of $24.95.

3c + 2b =$24.95

Equation 2: The cost of bananas is $6.50 less than a pound of cherries.

b= c - $6.50

We can substitute the second equation into the first one to solve for the cost of cherries per pound.

3c + (2)(c-$6.50)= $24.95

3c + 2c -$13.00 = $24.95

5c = $24.95 + $13.00

c = $7.59

Substituting the value of c to the second equation to solve for b.

b= $7.59 - $6.50 = $1.09

The combined cost of 1 pound of banana and 1 pound of cherries is $1.09 + $7.59 or $8.68.

For more information regarding the system of equations, please refer to brainly.com/question/25976025.

#SPJ4

4 0
1 year ago
Kyle works at a donut​ factory, where a​ 10-oz cup of coffee costs 95cents​, a​ 14-oz cup costs​ $1.15, and a​ 20-oz cup costs​
choli [55]
Let x = no. of 10 oz cups sold
Let y = no. of 14 oz cups sold
Let z = no. of 20 oz cups sold
:
Equation 1: total number of cups sold:
x + y + z = 24
:
Equation 2: amt of coffee consumed:
10x + 14y + 20z = 384
:
Equation 3: total revenue from cups sold
.95x + 1.15y + 1.50z = 30.60
:
Mult the 1st equation by 20 and subtract the 2nd equation from it:
20x + 20y + 20z = 480
10x + 14y + 20z = 384
------------------------ subtracting eliminates z
10x + 6y = 96; (eq 4)

Mult the 1st equation by 1.5 and subtract the 3rd equation from it:
1.5x + 1.5y + 1.5z = 36.00
.95x + 1.15y+ 1.5z = 30.60
---------------------------subtracting eliminates z again
.55x + .35y = 5.40; (eq 5)

Multiply eq 4 by .055 and subtract from eq 5:
.55x + .35y = 5.40
.55x + .33y = 5.28
--------------------eliminates x
0x + .02y = .12
y = .12/.02
y = 6 ea 14 oz cups sold 

Substitute 6 for y for in eq 4
10x + 6(6) = 96
10x = 96 - 36
x = 60/10
x = 6 ea 10 oz cups

That would leave 12 ea 20 oz cups (24 - 6 - 6 = 12)

Check our solutions in eq 2:
10(6) + 14(6) + 20(12) =
60 + 84 + 240 = 384 oz

A lot steps, hope it made some sense! I hope this helps!! ;D

3 0
3 years ago
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