3 years ago

"Find the value of x. Round to the nearest tenth. Refer to the attachment below. "

1 answer:

7 0

$Use\ \cos.\\\\\cos24^o=\dfrac{11}{x}\\\\\cos24^o\approx0.9135\\\\\dfrac{11}{x}\approx0.9135\ \ \ |cross\ multiply\\\\0.9135x\approx11\ \ \ \ |divide\ both\ sides\ by\ 0.9135\\\\x\approx12$

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Morgarella [4.7K]

Solution: We are given:

$Mean =78, Standard-deviation =6.3$

We know that a usual values of the test scores falls within 2 standard deviation from the mean.

Therefore, the minimum usual test score is:

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The maximum usual test score is:

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$78+12.6$

$90.6$

Therefore, the minimum and maximum “usual” values of the test scores are:

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3 years ago

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Answer:

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Step-by-step explanation:

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4 years ago

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miskamm [114]

Answer:

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Step-by-step explanation:

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4 years ago

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