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Nesterboy [21]
3 years ago
8

Given any two numbers, which is greater, the lowest common multiple of the numbers or the greatest common multiple?

Mathematics
1 answer:
tester [92]3 years ago
4 0

After you've calculated a least common multiple, always check to be sure your answer can be divided evenly by both numbers. Find the LCM of these sets of numbers. Multiply each factor the greatest number of times it occurs in any of the numbers. 9 has two 3's, and 21 has one 7, so we multiply 3 two times, and 7 once.

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If it is 5 degrees outside, and the temperature will drop 12
kolezko [41]

Answer:

-7 degrees

Step-by-step explanation:

Dropping 12 degrees means that it will get colder by 12 degrees. The colder it gets, the lower the temperature. 5 degrees - the current temperature, is going to be dropped by 12 degrees. To calculate this: 5-12 = -7 (degrees)

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Account B will cost less because

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Account B will cost

0.1*20 +1.5= 2+1.5= $3.5

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19.8 rounded to 1 s.f. is 20
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Explain how to find the mean of a data set
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Tobias dropped a tennis ball from a height of 60 meters. The time in seconds it takes for the ball to fall is 60 feet is 0.25 √6
aleksandrvk [35]

Answer:-1)The three sets of approximation of time will be

Time taken to fall tennis ball from height of 60 m =35.41014 s ≈35.410 s (to the nearest thousandth)

≈35.41s  (to the nearest hundredth)

≈35.5 seconds(to the nearest tenth)

2)Time by the ball to hit the ground =35.5 seconds

Step-by-step explanation:

Time taken to fall tennis ball from height of 60 feet =  0.25 √60 s

So,time taken to fall tennis ball from height of 1 foot =0.25√60 divided by 60=\frac{0.25\sqrt{60} }{60}s

We know that 1 m = 0.3048 foot

⇒60 m =60×0.3048=18.288 feet

therefore, Time taken to fall tennis ball from height of 60 m = 18.288 ×time taken to fall tennis ball from height of 1 foot=\frac{0.25\sqrt{60} }{60}\cdot18.288=35.41014\ s

∴Time taken to fall tennis ball from height of 60 m =35.41014 s ≈35.410 s (to the nearest thousandth)

≈35.41s  (to the nearest hundredth)

≈35.5 seconds(to the nearest tenth)

7 0
3 years ago
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