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Travka [436]
3 years ago
12

Please help me solve this problem.

Mathematics
1 answer:
levacccp [35]3 years ago
4 0

Answer:

  • h =  V/πr²
  • h = 10 inches

Step-by-step explanation:

  • V = πr²h

<u>1. Solving for h:</u>

  • V = πr²h
  • πr²h = V
  • πr²h/πr² = V/πr²
  • h =  V/πr²

<u>2. Finding the height of given cylinder, using formula above:</u>

  • V = 90π, r = 3 inches, h = ?
  • h =  V/πr²
  • h = 90π/π3²
  • h = 10 inches
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Answer:

Blue splat

Step-by-step explanation:

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3 years ago
Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )
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(a) First find the intersections of y=e^{2x-x^2} and y=2:

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So the area of R is given by

\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx

If you're not familiar with the error function \mathrm{erf}(x), then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

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So the area of S is given by

\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx
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\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx
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3 years ago
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noname [10]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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Chris saved x dollars and spent half of his savings buying video games. After earning an additional $15 cutting grass, he had $5
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