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3 years ago

Suppose you have five books in your bookbag. three books are novels

Mathematics

1 answer:

mixer [17]3 years ago

3 0

The complete question in the attached figure

we know that
The <span>probability on the first day is 3/5 since there are 3 novels out of 5 and when you take a book out at random, all of them have a equal chance of being picked. Since you returned the book to the bag, the next day too, we have the same probability. </span>

<span>Probability of a novel being grabbed both days is the product of the two probabilities-----> (3/5)*(3/5)----> 9/25

the answer is
9/25</span>

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Which relation is a function?

lina2011 [118]

Answer:

Step-by-step explanation:

For a relationship to be a function

Each value of x in the domain can only have 1 unique value of y in the range. That is, one-to-one correspondence.

The only relation which meets this criteria is B

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3 years ago

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I want to cover the curved surface of a cylinder with orange paper. My cylinder is 14” tall. The diameter is 3.5”. I have listed

Dominik [7]

Circumference of the cylinder = 3.14 x 3.5 = 10.99 = 11 inches
so D. 11 x 14 is correct for the first part

area of the top = PI x r^2 = 3.14 x 1.75^2 = 9.62 inches

top and bottom = 9.62 x 2 = 19.23 = A. 19 inches

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3 years ago

. Evaluate the expression below for x = 4. 6(x+8) (please

WITCHER [35]

Answer:

Step-by-step explanation:

6(x + 8) = Plug in x with 4

6(4 + 8) =

6(12) =

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2 years ago

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Please help!!! Which equation is in point-slope form and is depicted by the line in this graph?

Blizzard [7]

Y-y1=m(x-x1)
a point on the line is (x1,y1) and the slope is m

so
slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
so

points (-2,3) and (3,0)
slope is (0-3)/(3-(-2))=-3/(3+2)=-3/5
a point is (3,0) Or (-2,3)

so it could be
y-0=-3/5(x-3) or y-3=-3/5(x-(-2)) which is equal to y-3=-3/5(x+2)
that's the answer
B is answer

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3 years ago

A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32

olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

32*t = 32

t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

4 0

3 years ago