The correct answer that would best complete the given statement above would be this: A potential benefit of recruiting slow oxidative fivers for contraction before recruiting fast oxidative and fast glycolytic fibers might be because they are slower to respond, slow oxidative fibers must be stimulated first in order contract simultaneously with the faster fibers. Hope this answer helps.
<h3><u>Answer;</u></h3>
= 71.96%
<h3><u>Explanation</u>;</h3>
1 mole of CS2 = 76.133 g
1 mole of SO2 = 64.06 g
1 mole of CS2 reacts with 3 moles of Oxygen to produce 2 moles of SO2
Moles of CS2 in 12.5 g = 12.5/76.133
= 0.164 moles
Mass of SO2 = 0.164 mol × 2 × 64.06
= 21.01168 g
Therefore;
Percentage yield of SO2
= 15.12/21.01168 × 100%
<u> = 71.96%</u>
Answer:
A
Explanation:
Gram positive bacteria stain violet due to the presence of a thick layer of peptidoglycan in their cell walls, which retains the crystal violet these cells are stained with.
Answer:
WwNn
Explanation:
- Long wings (W) are dominant over short wings (w)
- Brown pigments (N) are dominant over yellow pigments (n)
A fly that is homozygous dominant for both traits (WWNN) is crossed with a fly that is homozygous recessive for both traits (wwnn).
All gametes produced by the WWNN individual will be <em>WN,</em> and all gametes produced by the homozygous recessive individual will be <em>wn</em>.
When the gametes from the two parents combine, the zygote will be heterozygous for both genes, with the genotype WwNn.
