X^4-11x^2+18=0 factor
1 answer:
Answer:
(x² - 9)(x² - 2) = 0
x = 3 or √2
Step-by-step explanation:
To factor a polynomial, you need to find two expression that when multiplied together using FOIL (first, outside, inside, last) will produce the polynomial. In this case the polynomial can be factored into:
(x² - 9)(x² - 2) = 0
Setting each of these expressions equal to '0':
x² - 9 = 0 or x² = 9 so √x² = √9 or x = 3
x² - 2 = 0 or x² = 2 so √x² = √2 or x = √2
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Answer:
22.81
Step-by-step explanation:
The distance formula can be used to find the distances between pairs of vertices. The perimeter is the sum of those distances.
<h3>Side lengths</h3>The distance formula is ...
d = √((x2 -x1)^2 +(y2 -y1)^2)
Using this formula the triangle side lengths are ...
AB = √((6 -(-2))^2 +(2 -2)^2) = √(8^2) = 8
BC = √((0 -6)^2 +(8 -2)^2) = √(6^2 +6^2) = 6√2
CA = √((-2 -0)^2 +(2 -8)^2) = √(4 +36) = √40
The perimeter of the triangle is the sum of these lengths:
P = 8 +6√2 +2√10 ≈ 22.8098
The perimeter is about 22.81 units.
Answer:
The vertex of the function is at (1,-25)
Step-by-step explanation:
I think your question missed key information, allow me to add in and hope it will fit the orginal one.
<em>Part of the graph of the function f(x) = (x + 4)(x-6) is shown below. </em>
<em>Which statements about the function are true? Select two </em>
<em>options. </em>
<em>The vertex of the function is at (1,-25). </em>
<em>The vertex of the function is at (1,-24). </em>
<em>The graph is increasing only on the interval -4< x < 6. </em>
<em>The graph is positive only on one interval, where x <-4. </em>
<em>The graph is negative on the entire interval </em>
My answer:
Given the factored form of the function:
f(x) = (x + 4)(x-6)
<=> f(x) =
We will convert to vertex form
<=> f(x) = () - 25
<=> f(x) =
=> the vertex of the function is: (1,-25)
We choose: a. The vertex of the function is at (1,-25)
Let analyse other possible answers:
<u>c. The graph is increasing only on the interval -4< x < 6.</u>
Because the parameter a =1 so the graph open up all over its domain and the vertex is the lowest point.
So the graph is increasing in the domain (1, +∞)
=> C is wrong
<u>d. The graph is positive only on one interval, where x <-4</u>
Wrong, The graph is positive only on one interval, where x > 6
<u>e. The graph is negative on the entire interval</u>
Wrong, The graph is negative only on one interval, where -4< x < 6.
