There are 52 weeks in a year and if she gets paid every two weeks then divide 52 by 2 to get 26 so she would get paid 26 times a year so divide her annual salary by 26 to get $1,346.15 every other week. So her biweekly salary is $1,346.15.
1. If the product of these integers is to be 1, then all of them must be either 1 or -1.
2. Since the product is positive (+1), it must be that there are an *even* number of negative ones (-1), if any.
3. If the sum were 0 it would mean that the number of +1's must equal the number of -1's. So that means there would have to be exactly 22/2=11 of each.
4. But if there were 11 of each, that means the number of -1's would be *odd* and there's no way the product could be +1 (as stated in 2 above).
Hence, the sum is never 0, if the product of 22 integers is equal +1.
Answer:
yes
Step-by-step explanation:
take for example
in the expression: 3x²+5x+2=0,
the coefficients here are +3 and +5 while +2 is a constant. +3 and +5 are coefficients of the variables x² and x respectively
Answer:
- <u>The complement of spinning any number less than 3, is spinning a number equal to or greater than 3.</u>
Explanation:
The complement of a subset is the subset of elements that are not in the given subset.
You must know which numbers the spinner has.
Assuming the spinner has the numbers 1, 2, 3, 4, the complement of spinning any number less than 3, is spinning a number that is not less than 3.
Then, that is spinning a number that is equal to or greater than 3.
The numbers that are equal to or greater than four, for a spinner that has the numbers 1, 2, 3, and 4 are 3 and 4.
Thus, the complement of spinning any number less than 3 is spinning a three or a four.
The domain is set of x-value.
Therefore, the domain of the relation Domain of R = {3,1,-1}
