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4 years ago

Abigail realizes that she has too much debt. What is a financially irresponsible decision for Abigail?

1 answer:

8 0

B would be the least wise...loans have interest which means that when you get around to paying them back you owe more than you borrowed and you can get yourself into even deeper debt. Hope this helps, and if you are able to do so, please mark Brainliest! Thanks!

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Given f(x)=3x^2+5 and g(x)=x−2 . What is (fg)(x) ? 3x^2−x+7 3x^3−6x2+5x−10 −3x^2+x−7 3x^3−10

wolverine [178]

For this case we have that by definition:

$(fg) (x) = f (x) * g (x)$

So:

$(fg) (x) = (3x ^ 2 + 5) (x-2)$

We apply distributive property that states that:

$(a + b) (c + d) = ac + ad + bc + bd$

In addition, we take into account that:

$+ * - = -$

$(fg) (x) = 3x ^ 3-6x ^ 2 + 5x-10$

Answer:

$3x ^ 3-6x ^ 2 + 5x-10$

Option B

6 0

3 years ago

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What is the next two number in the pattern?<br><br>1,8,27,64,125,...

kenny6666 [7]

248
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6 0

3 years ago

Help with 21 please 22 is not needed

Gwar [14]

We can't see the whole question :/

8 0

3 years ago

Can someone help me with this one

sergey [27]

The answer is 4. If you add 4 to any of the x values, it equals the y value next to it

6 0

3 years ago

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Use the Counting Principle to find the probability. Choosing the 7 winning lottery numbers when the numbers are chosen at random

frozen [14]

Answer: 120

<u>Step-by-step explanation:</u>

Since the order of the numbers doesn't matter we can use the formula:

$\dfrac{n!}{r!(n-r)!}\quad \text{where n is the quantity of items and r is the quantity chosen}\\\\\text{In this problem, there are 10 numbers (n = 10) and 7 to be chosen (r = 7)}\\\\_{10}C_{7}=\dfrac{10!}{7!(10-7)!}\\\\.\qquad=\dfrac{10!}{7!3!}\\\\.\qquad=\dfrac{10\times 9\times 8\times 7!}{7!\times 3\times 2\times 1}\\\\.\qquad=10\times 3\times 4\\\\.\qquad=120$

7 0

3 years ago

Read 2 more answers