X^3 - 6x^2 + 11x - 6 = 0
f(1) = 1^3 - 6(1)^2 + 11(1) - 6 = 1 - 6 + 11 - 6 = 0
This means that x - 1 is a factor of x^3 - 6x^2 + 11x - 6 = 0
x^2 - 5x + 6
___________________
x - 1 | x^3 - 6x^2 + 11x - 6
- | x^3 - x^2
|______________
| -5x^2 + 11x - 6
- | -5x^2 + 5x
|_____________________
| 6x - 6
- | 6x - 6
x^3 - 6x^2 + 11x - 6 = (x - 1)(x^2 - 5x + 6) = (x - 1)(x - 2)(x - 3)
Therefore, solutions to x^3 - 6x^2 + 11x - 6 are 1, 2 and 3.
After saving for 30 years, Hamilton would have contributed $99,000 and made a total interest of $50,722.57.
Hamilton will indeed have $149,722.57 at the end of 30 years.
Out of this, the amount he would have contributed is:
<em>= Amount contributed per month x Number of months contributed </em>
= 275 x 30 years x 12 months
= $99,000
The amount that would be interest is:
<em>= Total amount accumulated - Amount contributed </em>
= 149,722.57 - 99,000
= $50,722.57
In conclusion, Hamilton would have contributed $99,000 and made $50,722.57 in interest.
<em>Find out more at brainly.com/question/11741992. </em>
Answer:
36
Step-by-step explanation:
just do order of operations
there are atleast 4 pair of parallel faces shown
Answer:
See below
Step-by-step explanation:
The measure of all the arcs can be obtained by using 'Central angle and its corresponding arc theorem'.
1. The measure of arc AD is 
2. The measure of arc ABC is 
3. The measure of arc ADB is 
4. The measure of arc BD is 
