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3 years ago

Evaluate the exact value: tan(pi/6)

Mathematics

2 answers:

IRISSAK [1]3 years ago

6 0

The answer is sq root 3/3.

---------Apex

Sedbober [7]3 years ago

4 0

Pi/6 = 180°/6 = 30°

This produces a triangle that has 30-60-90 angles.

Its short leg will measure = y = sinΘ
Its long leg will measure = x = √1-y² = sin(2Θ)
Its hypotenuse will measure = 1

Tangent Θ = opposite / adjacent or short leg / long leg
Tan(pi/6) = 1/3 √3

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33 1/3% of 360 please help I don’t understand

Mars2501 [29]

Answer:

33 1/3% of 360 is 120

Step-by-step explanation:

33 1/3 can be converted to 33.333% or simply just 1/3, divide 360 by 3 to get your answer which is 120.

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What is 6 5/3 x 5 7/8 < 42

Eddi Din [679]

Answer:

The left side 45.041¯645.0416‾ is not less than the right side 42 which means that the given statement is false.

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3 years ago

MARK AS BRAINLEST!<br> 5 + x = 5

n200080 [17]

Answer:

x = 0

Step-by-step explanation:

You know the answer to this because you know the identity element for addition is 0: 5 + 0 = 5.

Or, you can make use of the addition property of equality and add -5 to both sides of the equation:

5 - 5 + x = 5 - 5

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Mikey has $100 to spend on books. She wants to buy at least 14 books. Hardback books cost $15.00 and paperback books cost $7.00.

fomenos

A. x+y<100
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3 years ago

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Jlenok [28]

Answer:

$x>2$

Step-by-step explanation:

When given the following inequality;

$(x^2+x-3):(x^2-4)\geq1$

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

$\frac{x^2+x-3}{x^2-4}\geq1$

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

$\frac{x^2+x-3}{x^2-4}-1\geq0$

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

$\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0$

Perform the operation on the other side distribute the negative sign and combine like terms;

$\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0$

Factor the equation so that one can find the intervales where the inequality is true;

$\frac{x+1}{(x-2)(x+2)}\geq0$

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

$-1, 2, -2$

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

$x\leq-2\\-2$

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

$x\leq-2$ -> negative

$-2$ -> neagtive

$-1\leq x$ -> neagtive

$x>2$ -> positive

Therefore, the solution to the inequality is the following;

$x>2$

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2 years ago