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Andru [333]
3 years ago
12

Quadrilateral abcd is inscribed in a circle choose a statement for each step in the proof that proves ABCD is a square

Mathematics
1 answer:
mamaluj [8]3 years ago
8 0

Answer:

The four sides of the lines tangent to the circle are equal.

Step-by-step explanation:

Inscribed circle is inside the four or more lines of a geometric shape. In the given inscribed circle the there are four lines which are tangent to the circle. The four line are equal in length and two of the lines are parallel. This confirms that the geometric shape is a square.

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The two linear functions f(x) and g(x) are shown below.<br> Which of the following is true
Vlada [557]

Answer:

C}

Step-by-step explanation:

5 0
3 years ago
Consider this equation. cos(theta) = (-2√5)/5. If theta is an angle in quadrant II, what is the value of sin(theta)? NO LINKS!!!
vlada-n [284]
  • In second quadrant sin and cosec are positive

\\ \tt\hookrightarrow sin^2\theta=1-cos^2\theta

\\ \tt\hookrightarrow sin^2\theta=1-(\dfrac{-2\sqrt{5}}{5})^2

\\ \tt\hookrightarrow sin^2\theta=1-\dfrac{20}{25}

\\ \tt\hookrightarrow sin^2\theta=\dfrac{5}{25}

\\ \tt\hookrightarrow sin\theta=\dfrac{\sqrt{5}}{5}

\\ \tt\hookrightarrow sin\theta=\dfrac{1}{\sqrt{5}}

5 0
2 years ago
Help out?? Mathematics image.
Brilliant_brown [7]

Answer: (12) ∠1 = 20° (13) ∠2 = 50° (14) ∠3 = 15° (15) UV = 80° (16) AB = 40°  (17) ABC <em>or</em>  180° - CD (18) BC - 140°  (19) ABC = 150°

<u>Step-by-step explanation:</u>

12) \frac{1}{2}(UV - ST) = ∠1

\frac{1}{2}(80 - 40) = ∠1

\frac{1}{2}(40) = ∠1

20 = ∠1

13) \frac{1}{2}(UV + ST) = ∠2

\frac{1}{2}(70 + 30) = ∠2

\frac{1}{2}(100) = ∠2

50 = ∠2

14) \frac{1}{2}(VB - BS) = ∠3

\frac{1}{2}(60 - 30) = ∠3

\frac{1}{2}(30) = ∠3

15 = ∠3

15) \frac{1}{2}(UV - ST) = ∠1

\frac{1}{2}(UV - 20) = 30

UV - 20 = 60

UV = 80

16) ∠1 = arc AB

     ∠1 = 40

              arc AB = 40

17) arc AB + arc BC = arc AC

                               = 180 = arc CD  

18) ∠1 + ∠2 + ∠3 = 180

   20 + ∠2  + 20 = 180

            ∠2 + 40 = 180

                      ∠2  = 140

19) ∠1 + ∠ 2 = arc ABC

     ∠1 + ∠2 + ∠3 = 180

    arc ABC + 30 = 180

            arc ABC = 150


4 0
3 years ago
Which of the following are incorrect expressions for slope?
vfiekz [6]

Answer:

Option B and C are correct.

\frac{x_2-x_1}{y_2-y_1}

\frac{run}{rise} are the expression incorrect for slope

Step-by-step explanation:

Slope is defined as the change in the dependent variable  relative to the change in the dependent variable

or the ratio of the horizontal changes to vertical changes between any two points on the graph of the line.

The vertical changes between any two points is rise

The horizontal changes between any two points is run.

Formula for slope is given by:

For any two points (x_1, y_1) and (x_2, y_2)

then slope is:

\text{Slope} =\frac{rise}{run}= \frac{y_2-y_1}{x_2-x_1}

or we can write this as:

Δy = y_2-y_1

Δx = x_2-x_1

⇒\text{Slope} = \frac{\triangle y}{\triangle x}

Therefore, the expression which are incorrect for slope  are;

\frac{x_2-x_1}{y_2-y_1}

\frac{run}{rise}

8 0
3 years ago
Read 2 more answers
What is the domain of this function? 
hichkok12 [17]

Answer:

no real numbers

Step-by-step explanation:

5 0
2 years ago
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