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Mrac [35]
3 years ago
9

What is 2/3 add 3/4? Thank you

Mathematics
1 answer:
Tanzania [10]3 years ago
5 0
The answer is 1 and  5/12. Hope I helped!
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Solve solve solve solve
Alex17521 [72]

Answer:

64pi

Step-by-step explanation:

area= pi * r^2

7 0
3 years ago
Read 2 more answers
for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b
marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

               ⇒    300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

                                                = 101/2 (300+100)

                                                = 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4        

7 0
1 year ago
Help question is on the attachment​
miv72 [106K]

Answer:

7/12

Step-by-step explanation:

2x6 =12 for the dinominator the nummarraton is 6 +1 =7

4 0
3 years ago
to analyze the test scores of students in a math class, would a teacher use a dot plot or histogram to represent the scores? bri
frutty [35]
A bar graph would be a better choice because it is able to show how often he/she has gotten a good score.
5 0
3 years ago
Read 2 more answers
H(x)=2x-6 find the value. -2[h(3)]
defon

Answer:

-2[h(3)] = 0

Step-by-step explanation:

Step 1: Define

h(x) = 2x - 6

Step 2: Find h(3)

h(3) = 2(3) - 6

h(3) = 6 - 6

h(3) = 0

Step 3: Find -2[h(3)]

-2(0)

0

3 0
3 years ago
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