Calculate the specific heat for as air if 1500.0 joules are required to raise the temperature of 50.0g from 0.0c to 40.0c
1 answer:
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Explanation:
(a). The given data is as follows.
Volume of one glass of water = ml = 220 ml
Volume of 4 glass of water = = 880 ml
We known that density of water is 1 g/ml. Therefore, calculate the mass of water as follows.
Mass of water =
= 880 gm
= 0.88 Kg (as 1 kg = 1000 g)
The relation between heat energy, mass and temperature change is as follows.
Q =
Putting the given values into the above formula as follows.
Q =
=
= 124.5 kJ
Hence, the body have to supply 124.5 kJ to raise the temperature of the water to 37 degree C.
(b). As we know that the heat of fusion of ice is 333 J/g.
So, energy required for g or 840 g is as follows.
= 279.72 kJ
Heat capacity of water= 4.184
Now, heat energy will be as follows.
Q =
= 130.03 kJ
Therefore, total heat required = (279.72 + 130.03) kJ
= 409.75 kJ
Hence, for the given situation your body should lose 409.75 kJ of heat.