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noname [10]
2 years ago
7

Remember: When recording genotype, two letters are used, a capital letter (D) for the dominant trait and a lower case (d) letter

for a recessive. By knowing the genotype of an organism, you can identify its phenotype, how it looks.
Determine what phenotypes would be possible: Bobtails in cats are recessive (t). Which of the genotypes would show the recessive trait?

a)TT
b)tt
c)Tt
d)Tt and tt
Chemistry
2 answers:
masya89 [10]2 years ago
8 0
Tt. i’m not fully sure but dominant traits usually always overpower recessive so i’m pretty sure in order for a recessive trait to show both parents need to give the recessive trait in order for it to show. i mean it’s in the words dominant and recessive
VMariaS [17]2 years ago
4 0
It’s D bc they both have the lowercase t
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The element europium exists in nature as two isotopes: has a mass of u and has a mass of u. The average atomic mass of europium
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Answer:

Problem Details

The element europium exists in nature as two isotopes:  151Eu has a mass of 150.9196 amu, and 153Eu has a mass of 152.9209 amu. The average atomic mass of europium is 151.96 amu. Calculate the relative abundance of the two europium isotopes.

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3 years ago
What is the difference between the mass number of an isotope and its atomic number?
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5 0
4 years ago
Calculate the mass of H2OH2O produced by metabolism of 1.6 kgkg of fat, assuming the fat consists entirely of tristearin (C57H11
kakasveta [241]

Answer: 1779.8g of H2O

Explanation:

C57H110O6 + O2 —> CO2 + H20

To calculate the amount of water(H2O) produced by the reaction of 1.6Kg tristearin(C57H110O6) and O2, we must first balance the equation.

To do so, add 2 in front of C57H110O6, 163 in front of O2, 114 in front of CO2 and 110 in front of H2O i.e

2C57H110O6 + 163O2 —> 114CO2 + 110H20

Next, we have to calculate the mass of tristearin(C57H110O6) that reacted and the mass of water produced from the balanced equation. This can be done by:

MM of C57H110O6 = (57x12) + (110x1) + (6x16) = 684 + 110 + 96 = 890g/mol

Mass conc of C57H110O6 = 890 x 2 = 1780g

MM of H2O = (2x1) + 16 = 18g/mol

Mass conc of H2O = 110 x 18 = 1980g

Next, we will find the amount of water produced by 1.6Kg(i.e 1600g) of tristearin(C57H110O6). This is done by:

From the equation,

1780g of C57H110O6 produced 1980g of H2O.

Therefore 1600g of C57H110O6 will produce = (1600x1980)/1780 = 1779.8g of H2O

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3 years ago
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