Answer:
Theoretical yield is 10.0g of HF.
Explanation:
Theoretical yield is defined as the yield of a reaction assuming a 100%.
In the reaction:
SiF₄(s) + 2H₂O(l) → 4HF(aq) + SiO₂(s)
2 moles of water produce 4 moles of HF.
4.51g of H₂O are:
4.51g ₓ (1mol/18.02g) = 0.250moles of water. Moles of HF:
0.250moles H₂O ₓ (4mol HF/2mol H₂O) = 0.500mol HF
In grams:
0.500mol HF ₓ (20.01g / 1mol) = <em>10.0g of HF - theoretical yield-</em>
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I hope it helps!
The correct option is:
The latent heat of vaporization of water is given by option D. 22,590J
Latent heat of vaporization:
Latent heat of vaporization is energy required to change 1 kg of liquid to gas at atmospheric pressure at its boiling point.
Also, Latent heat is the energy released or absorbed during a phase change.
Energy released during phase change is Exothermic process.
Whereas energy absorbed during phase change is Endothermic process.
Q=mL
Q= Latent heat
m= mass= 10 g
L= Latent heat of vaporization= 2,259 J/g
Putting the values in the above equation:
Q=10*2259
Q=22590 L
Learn more about 1st law of thermodynamics here,
brainly.com/question/20114432
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higher Ka value= stronger acid
stronger acids have weaker conjugate bases, so the acid with the strongest conjugate base would be acetic acid
Answer:
Explanation:
I assume the volume is 2.50 L. A volume of 25.0 L gives an impossible answer.
We have two conditions:
(1) Mass of glucose + mass of sucrose = 1.10 g
(2) Osmotic pressure of glucose + osmotic pressure of sucrose = 3.78 atm
Let g = mass of glucose
and s = mass of sucrose. Then
g/180.16 = moles of glucose, and
s/342.30 = moles of sucrose. Also,
g/(180.16×2.50) = g/450.4 = molar concentration of glucose. and
s/(342.30×2.50) = s/855.8 = molar concentration of sucrose.
1. Set up the osmotic pressure condition
Π = cRT, so
Now we can write the two simultaneous equations and solve for the masses.
2. Calculate the masses
We have 0.229 g of glucose and 0.871 g of sucrose.
3. Calculate the mass percent of sucrose
