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pshichka [43]
4 years ago
10

I need HELP Quick!!!

Mathematics
2 answers:
IRISSAK [1]4 years ago
7 0

Answer:

Step-by-step explanation:

d

kow [346]4 years ago
6 0
D. the values of x is 8
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Sydney invested $440 in an account paying an interest rate of 5.6% compounded daily. Assuming no deposits or withdrawals are mad
stealth61 [152]

Answer:

The time required to get  a total amount of $ 640.00  from compound interest on a principal of $ 440.00  at an interest rate of 5.6% per year  and compounded 365 times per year  is approximately 7 years.

Step-by-step explanation:

Given

  • Principle Amount P = $440
  • Accrued Amount A = $640
  • Interest rate r = 5.6% = 0.056
  • Compounded daily n = 365

To determine:

Time period t = ?

Using the formula

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

solving for t

t = ln(A/P) / n[ln(1 + r/n)]

substituting the values A = 640, P = 440, n = 365 and r = 0.056

t = ln(640/440) / ( 365 × [ln(1 + 0.00015342465753425/365)] )

t = 6.691

t ≈ 7  (nearest year)

Therefore, the time required to get  a total amount of $ 640.00  from compound interest on a principal of $ 440.00  at an interest rate of 5.6% per year  and compounded 365 times per year  is approximately 7 years.

4 0
3 years ago
Solve each equation.Show work plz
Nadusha1986 [10]
29. 5/2× 2/5×=5/2×7  multiply the equation by the reciprocal of the coefficient 

x= 5/2×7/1 <span> reduce the numbers with 5,2. convert the expression into a fraction 
</span><span>
x= 5</span>×7/2×1
<span>
x= 35/2

32. a= 19/6


2 3/4a = 19 1/4               divide both sides of the equation by 1/4

2</span>×3a=19                              calculate the product <span>
</span>
6a=19                                    divide both sides by 6

a=19/6

6 0
3 years ago
-4v³+11v²-6v how to factor
Nady [450]

-4v^3+11v^2-6v=-v(4v^2-11v+6)=-v(4v^2-8v-3v+6)\\\\=-v[4v(v-2)-3(v-2)]=-v(v-2)(4v-3)

4 0
3 years ago
9. Determine the equation of a line that passes though the points (3,-4) and (6,2). [​
stira [4]

Answer:

y=2x-10

Step-by-step explanation:

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (3,-4), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=3 and y1=-4.

Also, let's call the second point you gave, (6,2), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=6 and y2=2.

Now, just plug the numbers into the formula for m above, like this:

m=

2 - -4

6 - 3

or...

m=

6

3

or...

m=2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

3 0
3 years ago
1.
Olegator [25]
Hope this helps somewhat

7 0
3 years ago
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