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lora16 [44]
3 years ago
9

Jimmy loaded three bags of sand into his wheelbarrow. The bags weighed 24

Mathematics
1 answer:
Rudik [331]3 years ago
3 0
The whole numbers add up to 100. So now we are left with 1/2 or 0.5, 3/5 or .60, and 1/8 or .125. Those add up to 1.225 so the amount of sand in pounds in the wheelbarrow is 101.225. Hope I helped! If you have any questions just leave a comment.
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1.) Solve 2x^2-12x+20=0 using the quadratic solution set? What is the solution set?
marshall27 [118]
Please, share just ONE problem at a time.  Thanks.

<span>Solve 2x^2-12x+20=0:
Simplify this by dividing each term by 2:  x^2 - 6x + 10 = 0

Identify a, b and c:  a=1, b=-6 and c=10.  Then b^2=36.

Write out the solutions using the quadratic formula:

        6 plus or minus sqrt(36-40)
x = ---------------------------------------
                            2

sqrt(36-40) = sqrt(-4) = plus or minus i2

Then:
 
         6 plus or minus i2
x = --------------------------- (answer)
                  2</span>
4 0
2 years ago
I need help, someone please explain. I don't need the answers i just don't get it.
shepuryov [24]
What answers well whats the question?
4 0
2 years ago
Six more than nine times a Number is 456
Nuetrik [128]
Let the number = x
It would be: 9x + 6 = 456
9x = 456 - 6
9x = 450
x = 450 / 9
x = 50

In short, Your Answer would be 50

Hope this helps!
8 0
3 years ago
Do these two in the figure appear to be similar?
iVinArrow [24]

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3 years ago
Which of the following could be used to calculate the area of a sector in the circle shown below
lara [203]

Answer:

Therefore the Last option is correct

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

Step-by-step explanation:

Given:

Radius = r = 8 in

θ = 42°

To Find:

Area of Sector = ?

Solution:

We know that

\textrm{Area of Sector}=\pi (Radius)^{2}\times \frac{\theta}{360}

Substituting the given values in the formula we get

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

Which is the required Answer.

Therefore the Last option is correct

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

8 0
2 years ago
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