The dimensions of a room are determined by its length, width and height. In this problem we will assign a length of 12', a width of 13', and a height of 8' (as standard ceiling heights in most homes are 8' high). To calculate the amount of molding needed for strips at the top of the room and the bottom of the room we need to find the perimeter of the room. A length of 12' and a width of 13' make this room a rectangle. Determine the perimeter by adding 12' + 13' and multiplying the sum by 2 to get 50'. Multiply 50' x 2 to account for a decorative strip of molding at the floor and the ceiling and you get 100' total molding needed.
1. Linear Pair Postulate
2. MAngle 3
3.Angle 3
4.Angle Congruence Postulate
Hope this helps!
-Soul
Answer:
3,2 and -2
because you can't make denominator zero
and only these will make deno. zero
680/17=40. Therefore the height of the rectangle is 40 and the width is 17. so 40+40+17+17= c) 114 feet
Answer:
H=9;8)
B=(5;4) (ball)
R=(7;0) (hit point)
B'=symetric of B axis perpendicular of x in R
B'=(7+(7-5);4)=(9;4)
Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14
Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14
Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4 No!
you will not make your putt
Step-by-step explanation:
