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3 years ago

What is an equation of the line that passes through the point (-4,-3) and is perpendicular to the line 2x+3y=15

Mathematics

1 answer:

Katen [24]3 years ago

5 0

Answer:

The equation would be y = 3/2x + 3

Step-by-step explanation:

First we have to find the slope of the original line. We can do this by solving for y.

2x + 3y = 15

3y = -2x + 15

y = -2/3x + 5

Now that we have the slope of -2/3, we know the slope of the new line will be 3/2. This is because perpendicular lines have opposite and reciprocal slopes. We can use that and a point in point-slope form to find the equation.

y - y1 = m(x - x1)

y + 3 = 3/2(x + 4)

y + 3 = 3/2x + 6

y = 3/2x + 3

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