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3 years ago

7

What is an equation of the line that passes through the point (-4,-3) and is perpendicular to the line 2x+3y=15

1 answer:

Katen [24]3 years ago

5 0

Answer:

The equation would be y = 3/2x + 3

Step-by-step explanation:

First we have to find the slope of the original line. We can do this by solving for y.

2x + 3y = 15

3y = -2x + 15

y = -2/3x + 5

Now that we have the slope of -2/3, we know the slope of the new line will be 3/2. This is because perpendicular lines have opposite and reciprocal slopes. We can use that and a point in point-slope form to find the equation.

y - y1 = m(x - x1)

y + 3 = 3/2(x + 4)

y + 3 = 3/2x + 6

y = 3/2x + 3

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I NEED THIS ASAP PLEASE

ella [17]

Answer:

Step-by-step explanation:

This is modeled after an exponential function which, at its simplest, is

$y=a(b)^x$ where, for us and in this particular situation, y is the final height, a is the initial height, b is the rate of growth or decline, and x is the number of bounces. We know the initial height is 20, but we need to find the rate of decline. Rewriting the formula to model a rate of decay or decline is

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3 years ago

Given: segment PT || segment QS, segment PT ≅ segment QS, ∠T ≅ ∠S<br> Prove: ΔPQT ≅ ΔQRS

vfiekz [6]

Segment PT || segment QS, Given

segment PT ≅ segment QS,

∠T ≅ ∠S

Angle TPQ = Angle SQR PR is a transversal cutting parallel segments SQ and TP

So....it makes corresponding angles TPQ and SQR equal

ΔPQT ≅ ΔQRS ASA congruency

4 0

3 years ago

Which postulate or theorem proves that these two triangles are congruent,

sukhopar [10]

SAS. Sides because PN and MN are congruent as well as RN and QN. Since angle PNQ and angle MNR are vertical angles they are also congruent.

5 0

3 years ago

Read 2 more answers

(x+3)(3x² - 5x - 10) multiply polynomial

brilliants [131]

Answer:

$\boxed{\sf{3x^3+4x^2-25x-30}}$

Step-by-step explanation:

$\underline{\text{SOLUTION:}}$

To isolate the term of x from one side of the equation, you must multiply by a polynomial.

$\underline{\text{GIVEN:}}$

$:\Longrightarrow: \sf{(x+3)(3x^2 - 5x - 10)}$

<u>You have to solve with parentheses first.</u>

$:\Longrightarrow \sf{x\cdot \:3x^2+x\left(-5x\right)+x\left(-10\right)+3\cdot \:3x^2+3\left(-5x\right)+3\left(-10\right)}$

<u>Solve.</u>

$\sf{x*3x=3x^3}$

x(-5x)=-5x²

$\sf{x(-10)=-10x}$

3*3x²=9x²

3(-5x)=-15x

3(-10)=-30

<u>Then, rewrite the problem down.</u>

$\sf{3x^3-5x^2-10x+9x^2-15x-30}$

<u>Combine like terms.</u>

$\Longrightarrow: \sf{3x^3-5x^2+9x^2-10x-15x-30}$

<u>Add/subtract the numbers from left to right.</u>

-5x²+9x²=4x²

$\Longrightarrow: \sf{3x^3+4x^2-10x-15x-30}$

<u>Solve.</u>

$\sf{-10x-15x=-25x}$

<u>Then rewrite the problem.</u>

$\Longrightarrow: \boxed{\sf{3x^3+4x^2-25x-30}}$

<u>Therefore, the correct answer is 3x³+4x²-25x-30.</u>

I hope this helps! Let me know if you have any questions.

6 0

2 years ago

Read 2 more answers

fgiga [73]

Answer:

A. y = 0.5(2)^x

Step-by-step explanation:

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is y = 0 .

Horizontal Asymptote:

y = 0

7 0

2 years ago