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Studentka2010 [4]
3 years ago
6

A ramp is 17 feet long, rises 8 feet above the floor, and covers a horizontal distance of 15 feet, as shown in the figure. The r

atio of to is equal to tan B.
Mathematics
2 answers:
puteri [66]3 years ago
5 0
Your answer is sin b and cos b 

SCORPION-xisa [38]3 years ago
3 0

In the given question, it is given that

ramp is 17 feet long, rises 8 feet above the floor, and covers a horizontal distance of 15 feet.

And we have to find the value of tan B.

And tangent of any angle is equal to the ratio of vertical by horizontal. That is

tan B = \frac{8}{15}

And that's the required missing ratio for tan B .


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7/12 fractions that is equivalent to 2/4
zhenek [66]

Answer:

Step-by-step explanation:

So we multiply 7 by 4, and get 28. Then we multiply 2 by 12, and get 24. Next we give both terms new denominators 12 × 4 = 48.

6 0
3 years ago
A portion of a line or Ray that extends from one point to another point is called what
Juli2301 [7.4K]

Answer: line segment

Step-by-step explanation:

A line segment is a ray that extends from one point to another. Hope this helps!

5 0
3 years ago
Read 2 more answers
Hannah has $47 left on her checking account. If she writes a check for $55,what will Hannah’s balance be? *
alexandr1967 [171]
47 minus 55 is -8 …..
8 0
3 years ago
PLEASE HELP!!!
Aliun [14]

Answer:

a. 8.75 M NaOH

b. 0.425 M CuCl₂ or 0.43 M CuCl₂

c. 0.067 M CaCO₃ or 0.07 M CaCO₃

Step-by-step explanation:

Molality is computed using the formula:

M = \dfrac{Moles\:of\:solute}{Liters\:of\:solution}

So first thing you need to do is determine how many moles of solute there are and divide it by the solution in liters.

Converting mass to moles, you need to get the mass of each solute per mole. You can use the periodic table to get the atomic mass (which is the grams per mole of each atom) of each of the elements involved. Then add them up and you will have how many grams per mole of each compound.

1. 35.0g of NaOH in 100ml H₂O

Element         number of atoms            atomic mass           TOTAL

Na                              1                   x             22.99g/mol  =    22.99g/mol

O                                1                   x             16.00g/mol   =    16.00g/mol

H                                1                   x                1.01g/mol   =<u>       1.01g/mol</u>

                                                                                                 40.00g/mol

This means that the molecular mass of NaOH is 40.00 g/mol

Then we use this to convert 35.0g of NaOH to moles:

35.0g \:of\:NaOH \times \dfrac{1\:mole\:of\:NaOH}{40.00g\:of\:NaOH} = \dfrac{35.0\:moles\:of\:NaOH}{40.00}=0.875\:moles\:of\:NaOH

Now that you have the number of moles we divide it by the solution in liters. Before we can do that you have to conver 100ml to L.

100ml\times\dfrac{1L}{1000ml} = 0.1 L

Then we divide it:

\dfrac{0.875\:moles\:of\:NaOH}{0.1L of solution} = 8.75M\: NaOH

2. 20.0g CuCl₂ in 350ml H₂O

Element         number of atoms            atomic mass           TOTAL

Cu                              1                   x             63.55g/mol  =    63.55g/mol

Cl                               2                   x             34.45g/mol   =   <u>70.90g/mol</u>

                                                                                                134.45g/mol

20.g\:of\:CuCl_2\times\dfrac{1\:mole\:of\:CuCl_2}{134.45\:g\:of\:CuCl_2}=0.1488\:moles\:of\:CuCl_2

350ml = 0.350L

\dfrac{0.1488\:moles\:of\:CuCl_2}{0.350L\:of\:solution}=0.425M\:CuCl_2

3. 3.35g CaCO₃ in 500ml

Element         number of atoms            atomic mass           TOTAL

Ca                              1                   x             40.08g/mol  =    40.08g/mol

C                                1                   x              12.01g/mol   =    12.01g/mol

O                                3                  x              16.00g/mol   =<u>   48.00g/mol</u>

                                                                                                100.09g/mol

3.35g\:of\:CaCO_3\times\dfrac{1\:mole\:of\:CaCO_3}{100.09\:g\:of\:CaCO_3}=0.0335\:moles\:of\:CaCO_3

500ml = 0.5L

\dfrac{0.0335\:moles\:of\:CaCO_3}{0.5L}=0.067M\:CaCo_3

4 0
3 years ago
The temperature was -3 C last night. It is now -4 C. What was the change in temperature
natulia [17]

-1 C, that's the only logical answer I can think of. Or does it have to be in F?

6 0
3 years ago
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