Answer:
The expression is not defined in a set of real numbers.
The square root of a negative number is not defined in the set of real numbers.
Answer:
The equation of line is: 
Step-by-step explanation:
We need to find an equation of the line that passes through the points (-6, -2) and (-3, 2)?
The equation of line in slope-intercept form is: 
where m is slope and b is y-intercept.
We need to find slope and y-intercept.
Finding Slope
Slope can be found using formula: 
We have 
Putting values and finding slope

So, we get slope: 
Finding y-intercept
Using point (-6,-2) and slope
we can find y-intercept

So, we get y-intercept b= 6
Equation of required line
The equation of required line having slope
and y-intercept b = 6 is

Now transforming in fully reduced form:

So, the equation of line is: 
Answer:
y = (x/(1-x))√(1-x²)
Step-by-step explanation:
The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:
x = r·cos(θ)
y = r·sin(θ)
x² +y² = r²
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r = sec(θ) -2cos(θ)
r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)
r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²
(x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations
x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor
y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)

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The attached graph shows the equivalence of the polar and rectangular forms.