Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.
<h3>What is Ionic Compound ?</h3>
An ionic compound is defined as the compound made up of ions that formed charge particles when an atom loses or gains electrons.
<h3>What is Cation ?</h3>
Cations are positively charged ions. It forms when an element lose one or more electrons.
The cation which has 18 electrons is Sn. Sn react with fluorine to form an ionic compound with the formula SnF₄ because Sn is large and F is very small in size.
Thus from the above conclusion we can say that Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.
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Answer:
Following are the solution to this question:
Explanation:
Please find the complete question in the attachment.
Start of Laboratory
Dissolve 2-naphthol in the round bottom flask with ethanol.
Add pellets of sodium hydroxide and hot chips. Attach a condenser.
Heat for 20 minutes under reflux, until the put a burden dissolves.
After an additional hour, add 1-Bromobutane and reflux.
Pour the contents into a beaker with ice from a round bottom flask.
On a Bachner funnel, absorb the supernatant by vacuum filtration.
Utilizing cold water to rinse the material and dry that on the filter.
Ending of the Lab
Answer:
a measure of how acidic/base water is.
Explanation:
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Is bubble chamber one of your choices? Bubble chamber sounds like a good fit for the question.
Answer:
Yes. The solution would be optically active.
Explanation:
Diastereomer are defined as the image that is non mirror and non -identical. It is made up of two stereoisomers. They are formed when the two stereoisomers or more than two stereoisomers of the compound have the same configuration at the equivalent stereocenters.
In the given context, as the product given is a diastereomeric mixture, the product would have an optical activity in total.
So the answer is Yes.