Element m reacts with fluorine to form an ionic compound with the formula mf4. the m cation has 18 electrons. element m is:____.

1 answer:

6 0

Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.

<h3>What is Ionic Compound ?</h3>

An ionic compound is defined as the compound made up of ions that formed charge particles when an atom loses or gains electrons.

<h3>What is Cation ?</h3>

Cations are positively charged ions. It forms when an element lose one or more electrons.

The cation which has 18 electrons is Sn. Sn react with fluorine to form an ionic compound with the formula SnF₄ because Sn is large and F is very small in size.

Thus from the above conclusion we can say that Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.

Learn more about the Ionic Compound here: brainly.com/question/2687188

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For a particular isomer of C8H18, The following reaction produces 5093.7 KJ of heat per mole of C8H18(g) consumed under standere

Aleks04 [339]

02(g) = 0 kj/mol
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<span>add -5324.2 to -5094 </span>
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7 0

3 years ago

The decomposition of NI3 to form N2 and I2 releases −290.0 kJ of energy. The reaction can be represented as 2NI3(s)→N2(g)+3I2(g)

EastWind [94]

Answer:

-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.

Explanation:

Mass of nitrogen triiodide = 20.0 g

Moles of nitrogen triiodide = $\frac{20.0 g}{395 g/mol}=0.05063 mol$

$2NI_3(s)\rightarrow N_2(g)+3I_2(g), \Delta H_{rxn}=-290.0 kJ$

According to reaction, 2 moles of nitrogen triiodide gives 290.0 kilo Joules of heat on decomposition ,then 0.05063 moles of nitrogen triiodide will give :

$\frac{-290.0 kJ}{2}\times 0.05063=-7.34 kJ$